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nadezda [96]
2 years ago
15

Helpppppp!!!!!!!! On part A and B plzzzz

Mathematics
2 answers:
sashaice [31]2 years ago
6 0
Part a is 50 and part b is 20 at a 90 degree angle
mina [271]2 years ago
4 0

Answer:

Vertex=(0.5,9)

Axis-of-symmetry=0.5

<u>Skills needed: Quadratic Graphing</u>

Step-by-step explanation:

1) We need to first understand what the vertex is. In a parabola, the vertex is either the highest or lowest point. If the parabola is like a mountain (with the peak at the top), then it is the highest point. If the parabola is like a valley (with a divot like point at the lowest part), then the vertex is the lowest point.

---> On the graph in the picture, it is like a mountain.

- This mean it is the highest point for this graph.

The highest point would be (0.5, 9), as to the left of that point it goes down, and also to the right of the point it starts going down.

(0.5, 9) is the vertex.

2) The axis-of-symmetry is always the x-axis value of the vertex when given a parabola. This is basically the x-axis value for which the equation can be folded over with symmetry.

---> Axis of symmetry here is 0.5

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I need help on this one
umka2103 [35]
You seem to have gotten m∠2. Remember that ∠1 and ∠2 are alternate interior angles, meaning they're both equal. Since they gave you m∠1 as being 26°, you now know the measure of ∠2.

As for m∠3 and m∠4, If you look at ∠3 you'll see that it is complementary to ∠1 (They both add up to 90°), so if you subtract m∠1 from 90° you'll have found m∠3. You find m∠4 the same way.

Hope this helped.
6 0
2 years ago
10-24
jasenka [17]

Answer:

Like this...

Step-by-step explanation:

The best represented graph should look something like this :)

(program used is Desmos)

8 0
2 years ago
Find the length of the altitude to the hypotenuse. Round the answer to the nearest tenth, if needed.
SVEN [57.7K]
To solve this, it might be easier to draw it out (see the picture below). I split it into two triangles and used trig functions to find the altitude. I used the big triangle to find theta, and the used theta to find the side of the altitude. *remember that sine= opposite/hypotenuse*

8 0
3 years ago
A rectangular swimming pool measures 7.5 m by 4.5 m. It is completely surrounded by a fence parallel to each edge of the pool an
Illusion [34]

The total length of the fence is 48 m if the rectangular swimming pool measures 7.5 m by 4.5 m.

<h3>What is rectangle?</h3>

It is defined as the two-dimensional geometry in which the angle between the adjacent sides are 90 degree. It is a type of quadrilateral.

It is defined as the area occupied by the rectangle in two-dimensional planner geometry.

The area of a rectangle can be calculated using the following formula:

Rectangle area = length x width

It is given that:

A rectangular swimming pool measures 7.5 m by 4.5 m.

It is completely surrounded by a fence parallel to each edge of the pool and at a distance of 3 m from each edge of the pool.

The total length of the fence = 2(7.5+3×2 + 4.5+3×2)

The total length of the fence = 2(7.5+6 + 4.5+6)

The total length of the fence = 2(24)

The total length of the fence = 48 m

Thus, the total length of the fence is 48 m if the rectangular swimming pool measures 7.5 m by 4.5 m.

Learn more about the rectangle here:

brainly.com/question/15019502

#SPJ1

4 0
1 year ago
The owner of a football team claims that the average attendance at games is over 523, and he is therefore justified in moving th
USPshnik [31]

Answer:

C) There is not sufficient evidence to support the claim that the mean attendance is greater than 523.

Step-by-step explanation:

Let μ be the the average attendance at games of the football team

The claim: the average attendance at games is over 523

Null and alternative hypotheses are:

  • H_{0}: μ=523
  • H_{a}: μ>523

The conclusion is failure to reject the null hypothesis.

This means that <em>test statistic</em> is lower than <em>critical value</em>.  Therefore it is not significant, there is no significant evidence to accept the <em>alternative</em> hypothesis.

That is no significant evidence that the average attendance at games of the football team is greater than 523.

7 0
2 years ago
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