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2 years ago

if jesus can walk on water and I can walk on watermelon which is 90 percent water does that make me 90 percent jesus?

Mathematics

1 answer:

melamori03 [73]2 years ago

4 0

Yes!

step by step explanation: 90

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What is the answer<br><img src="https://tex.z-dn.net/?f=%20%7B5%7D%5E%7B%20-%207%7D%20%20%5Ctimes%20%20%7B5%7D%5E%7B12%7D%20%20%

garri49 [273]

Hey there!!

Simple equation :

mᵃ × mᵇ = m ᵃ⁺ᵇ

We have :

5⁻⁷ * 5¹² * 5⁻²

... 5⁻⁷⁺¹²⁻²

... 5¹²⁻⁹

... 5³

... 125

Hope my answer helps!!

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2 years ago

The radius of a circle is 3cm. What is the area of the circle? Use 3.14 for pie.

vekshin1

Answer: 28.26 square cm

Step-by-step explanation:

$A=\pi r^{2}=\pi(3)^{2} \approx 3.14(3)^{2} \approx \boxed{28.26 \text{ cm}^{2}}$

6 0

1 year ago

How do you solve 12x =144

julia-pushkina [17]

1st. Try to make x by itself. Divide 12 on each side.
After it will look like this

x=12

8 0

2 years ago

Read 2 more answers

A developer was buying land. He bought 4 acres at $1,863 per acre. He then spilt the land he purchased into 9 lots. How much sho

Tpy6a [65]

Answer:

$1862 ÷9=$207(each lot)

$207 ×4=$828

5 0

3 years ago

One container is filled with mixture that is 25% acid. A second container is filled with a mixture that is 55% acid. The second

algol13

Answer:

Therefore the third container contains $\frac{735}{17}\%$ = 43.23 % acid.

Step-by-step explanation:

Given that, One container is filled with the mixture that 25% acid. 55% acid is contain by second container.

Let the volume of first container be x cubic unit.

Since the volume of second container is 55% larger than the first.

Then the volume of the second container is

$= (V\times \frac{100+55}{100})$ cubic unit.

$=\frac{155}{100}V$ cubic unit.

The amount of acid in first container is

$=V\times \frac{25}{100}$ cubic unit.

$=\frac{25}{100}V$ cubic unit.

The amount of acid in second container is

$=(\frac{155}{100}V \times \frac{55}{100})$ cubic unit.

$=\frac{8525}{10000}V$ cubic unit.

Total amount of acid $=(\frac{25}{100}V+\frac{8525}{10000}V)$ cubic unit.

$=(\frac{2500+8525}{10000}V)$ cubic unit.

$=(\frac{11025}{10000}V)$ cubic unit.

Total volume of mixture $=(V+\frac{155}{100}V)$ cubic unit.

$=\frac{100+155}{100}V$ cubic unit.

$=\frac{255}{100}V$ cubic unit.

The amount of acid in the mixture is

$=\frac{\textrm{The volume of acid}}{\textrm{The amount of mixture}}\times 100 \%$

$=\frac {\frac{11025}{10000}V}{\frac{255}{100}V}\times 100\%$

$=\frac{735}{17}\%$

Therefore the third container contains $\frac{735}{17}\%$ acid.

5 0

3 years ago