How many times does 19 go into 115

Beth is writing out the steps using the "Shortest Route Algorithm". She just finished writing out all

JulijaS [17]

Answer:

ACBD; 7

Step-by-step Explanation:

The Route Algorigtm finds the short route that is efficient, in order to find the solution following pathways.

From the pictures from the complete question,

STEP #1, there exist, three routes, which are:

AB

AC,

and AD.

*AB is not viable because of the negative distance, so it can be removed .

* the AC distance is 3,and AD distance is 8. Therefore, AC can be selected and circled.is because of AC efficiency is high compare to AD.

*from selected AC, the possible routes are ACB; 3 and ACE; 6. which are route shown in #2

* ACB is circled, because it's more shorter than ACE

*The possible routes are ACBE; 8 and ACBD; 7. which are route shown in #3 . Therefore, route ACBD is circled because it's more shorter.

From the analysis of the algorithm, the route ACBD route is the shortest and the most efficient

5 0

3 years ago

Identify the variable expression that is not a polynomial.

Blababa [14]

I think the answer is A.33 not a polunomial

6 0

3 years ago

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For a certain river, suppose the drought length Y is the number of consecutive time intervals in which the water supply remains

AnnZ [28]

Answer:

a) There is a 9% probability that a drought lasts exactly 3 intervals.

There is an 85.5% probability that a drought lasts at most 3 intervals.

b)There is a 14.5% probability that the length of a drought exceeds its mean value by at least one standard deviation

Step-by-step explanation:

The geometric distribution is the number of failures expected before you get a success in a series of Bernoulli trials.

It has the following probability density formula:

$f(x) = (1-p)^{x}p$

In which p is the probability of a success.

The mean of the geometric distribution is given by the following formula:

$\mu = \frac{1-p}{p}$

The standard deviation of the geometric distribution is given by the following formula:

$\sigma = \sqrt{\frac{1-p}{p^{2}}$

In this problem, we have that:

$p = 0.383$

So

$\mu = \frac{1-p}{p} = \frac{1-0.383}{0.383} = 1.61$

$\sigma = \sqrt{\frac{1-p}{p^{2}}} = \sqrt{\frac{1-0.383}{(0.383)^{2}}} = 2.05$

(a) What is the probability that a drought lasts exactly 3 intervals?

This is $f(3)$

$f(x) = (1-p)^{x}p$

$f(3) = (1-0.383)^{3}*(0.383)$

$f(3) = 0.09$

There is a 9% probability that a drought lasts exactly 3 intervals.

At most 3 intervals?

This is $P = f(0) + f(1) + f(2) + f(3)$

$f(x) = (1-p)^{x}p$

$f(0) = (1-0.383)^{0}*(0.383) = 0.383$

$f(1) = (1-0.383)^{1}*(0.383) = 0.236$

$f(2) = (1-0.383)^{2}*(0.383) = 0.146$

Previously in this exercise, we found that $f(3) = 0.09$

So

$P = f(0) + f(1) + f(2) + f(3) = 0.383 + 0.236 + 0.146 + 0.09 = 0.855$

There is an 85.5% probability that a drought lasts at most 3 intervals.

(b) What is the probability that the length of a drought exceeds its mean value by at least one standard deviation?

This is $P(X \geq \mu+\sigma) = P(X \geq 1.61 + 2.05) = P(X \geq 3.66) = P(X \geq 4)$ .

We are working with discrete data, so 3.66 is rounded up to 4.

Either a drought lasts at least four months, or it lasts at most thee. In a), we found that the probability that it lasts at most 3 months is 0.855. The sum of these probabilities is decimal 1. So:

$P(X \leq 3) + P(X \geq 4) = 1$

$0.855 + P(X \geq 4) = 1$

$P(X \geq 4) = 0.145$

There is a 14.5% probability that the length of a drought exceeds its mean value by at least one standard deviation

8 0

3 years ago

Could mud wrestling be the cause of a rash contracted by Washington State University students in the spring of 1992? Physicians

Daniel [21]

Thank you for posting your question here at brainly. Feel free to ask more questions.

The best and most correct answer among the choices provided by the question is A. Between 0.05 and 0.01 .
 
Hope my answer would be a great help for you.

7 0

3 years ago

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Kevin is 3 times as old as Daniel. 4 years ago, Kevin was 5 times as old as Daniel. How old is kevin now?

puteri [66]

K = Kevin's age
D = Daniel's age

K = 3D

K - 4 = 5(D - 4)

Plug in 3D for the K values in the second equation.

3D - 4 = 5(D - 4) Use the Distributive Property
3D - 4 = 5D - 20 Add 4 to both sides
3D = 5D - 16 Subtract 5D from both sides
-2D = -16 Divide both sides by -2
D = 8
Now, plug that D value into the original equation.

K = 3D Plug in the D value
K = 3(8) Multiply
K = 24

Finally, you can double check your math.

4 years ago, Daniel would've been 4 and Kevin would be 20, so Kevin would've been 5 times as old as Daniel. And 8 x 3 = 24.

So, Kevin is 24.

3 0

3 years ago

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