Question

What is an equation of a line that passes through the point

Answer 1

Answer:  y = -(1/2)x + 3

Step-by-step explanation:

y = 2x - 1

This is in the format of y=mx + b, where m is the slope and b is the y-intercept (the value of y when x=0).

Perpendicular lines have a slope that is the negative inverse of the reference line.  The slope of this reference line is 2, so the slope of a perpendicular kline will be -(1/2).

This yields the equation y = -(1/2)x + b

To find the value of b, we can use the given point, (0,3) and use these values of x and y to solve for b:

y = -(1/2)x + b

3 = -(1/2)(0) + b

b = 3

The equation of a line perpendicular to y = 2x - 1 and goes through point (0,3) is:

y = -(1/2)x + 3