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2 years ago

The accompanying table shows the value of a car over time that was purchased for

Mathematics

1 answer:

Dafna1 [17]2 years ago

3 0

The value of the car after 11 years is $3137.18

<h3>exponential function</h3>

An exponential function is in the form:

y = abˣ

where a is the initial value of y, b is the factor, y, x are variables.

Let y represent the value of the car in dollars after x years. From the table:

When x = 0, y = 12700, hence:

12700 = ab°
a = 12700

When x = 2, y = 9849, hence:

9849 = 12700b²
b = 0.8806

The exponential function is:

y = 12700(0.8806)ˣ

For 11 years:

y = 12700(0.8806)¹¹ = 3137.18

The value of the car after 11 years is $3137.18

Find out more on exponential function at: brainly.com/question/12940982

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Reptile [31]

Answer:

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Given a second order polynomial expressed by the following equation:

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This polynomial has roots $x_{1}, x_{2}$ such that $ax^{2} + bx + c = a(x - x_{1})*(x - x_{2})$ , given by the following formulas:

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In this problem, we have that:

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$x_{1} = \frac{-3 + \sqrt{13}}{2*1} = 0.3$

$x_{2} = \frac{-3 - \sqrt{13}}{2*1} = -3.3$

The real zeros of f(x) are x = 0.3 and x = -3.3.

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3 years ago

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