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trasher [3.6K]
2 years ago
10

Help Me on this math equation​

Mathematics
1 answer:
igomit [66]2 years ago
4 0

Answer:

uhhhh what grade level is dis?

Step-by-step explanation:

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Please help me with this math problem <br>Evaluate C/2 - 3 + 6/D when c=14 and d=3
lbvjy [14]

\frac{c}{2}  - 3 +  \frac{6}{d }  =  \\  =  \frac{14}{2}  - 3 +  \frac{6}{3}  =  \\  = 7 - 3 + 2 =  \\ =  6
7 0
3 years ago
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Where is the hole for the following function located? mc005-1.jpg
alex41 [277]
The hole is located where the hole is part a

4 0
2 years ago
Hi there! i going to fail if you don´t answer :D :D
NARA [144]

Answer:

it will be 1/2

Step-by-step explanation:

because x×y={(6,2), (6, 8),(9,2), (9, 8)}

5 0
3 years ago
Can I get some help, it is due in 15 minutes and I need help. Thanks, any help appreciated
koban [17]

Well, I'm way past the 15 min mark, but here's how to do the question.


With this, you will need to use the distance formula, \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}, on XY, YZ, and ZX.



XY: \sqrt{(3-1)^2+(1-6)^2}


Firstly, solve inside the parentheses: \sqrt{(2)^2+(-5)^2}


Next, solve the exponents: \sqrt{4+25}


Next, solve the addition, and XY's distance will be √29



(The process is the same with the other 2 sides, so I'll go through them real quickly)


YZ:

\sqrt{(6-3)^2+(3-1)^2}\\ \sqrt{(3)^2+(2)^2}\\ \sqrt{9+4}\\ \sqrt{13}



ZX:

\sqrt{(1-6)^2+(6-3)^2}\\ \sqrt{(-5)^2+(3)^2}\\ \sqrt{25+9}\\ \sqrt{34}



Now that we got the 3 sides, we can add them up: \sqrt{29}+\sqrt{13} +\sqrt{34} =14.8


In short, your answer is 14.8, or the second option.

8 0
3 years ago
Which formula represents this sequence
marysya [2.9K]

Answer:

pretty sure its b

Step-by-step explanation:

8 0
1 year ago
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