Answer is c. -2 (cannot be in the solution set of w/-2)
because.
a) -1/-2 = 1/2 and 1/2 < 1
b) 1/-2 = -1/2 and -1/2 <1
d) 2/-2 = -1 and -1 <1
but
c) -2/-2 = 1 and 1 = 1
Answer:
d
Step-by-step explanation:
175,026, 175,027, 175,028, 175,029, 175,030, 175,031 Is the answer. Brainliest answer Please
Answer:
y is the dependent variable
Step-by-step explanation:
Answer:
dy/dx = e⁻²ᵗ (1 − t)
d²y/dx² = -e⁻³ᵗ (3 − 2t)
(1.5, ∞)
Step-by-step explanation:
x = eᵗ
y = te⁻ᵗ
dx/dt = eᵗ
dy/dt = -te⁻ᵗ + e⁻ᵗ
dy/dt = e⁻ᵗ (1 − t)
dy/dx = (dy/dt) / (dx/dt)
dy/dx = e⁻ᵗ (1 − t) / eᵗ
dy/dx = e⁻²ᵗ (1 − t)
d²y/dx² = d(dy/dx)/dt / (dx/dt)
d²y/dx² = (-e⁻²ᵗ − 2(1 − t) e⁻²ᵗ) / eᵗ
d²y/dx² = -e⁻²ᵗ (1 + 2(1 − t)) / eᵗ
d²y/dx² = -e⁻³ᵗ (3 − 2t)
The function is concave up when the second derivative is positive. -e⁻³ᵗ is always negative, so the second derivative is positive when 3 − 2t is negative.
3 − 2t < 0
3 < 2t
t > 3/2
Or, in interval notation, (1.5, ∞).
