The answer of a young diver is practicing his skills before an important team competition use the diagram below in order to analyze thee energies of the D
Answer:
Check Explanation.
Explanation:
(1). The force that will continue to move the sled toward the right and speeding up at steady rate(constant acceleration) = option C => The force is toward the right and is constant strength (magnitude).
(2). The force that will continue to move the sled toward the right and at Constant velocity = option G => No applied force is needed. This is because acceleration = 0,and force is also = 0.
(3). The force that will continue to move at steady rate and an acceleration to the right = option A => The force is toward the right and is decreasing in strength (magnitude).
(4). The force that will slow the sled moving to the right at steady rate(constant acceleration) = option F => The force is toward the left and is of constant strength (magnitude).
(5). The force that moves the sled rest toward the a steady (velocity) towards the left = option G => No applied force is needed.
Answer:
50.0543248872 ft
Explanation:
F = Load = 20 ton =
d = Diameter = 1.25 in
= Initial length = 50 ft
= Final length
A = Area =
Y = Young's modulus =
Young's modulus is given by
The length during the lift is 50.0543248872 ft
Answer:
Mobile
Explanation:
Plastoquinone has a similar structure and role to Ubiquinone, found in other electron transport chains. It's a mobile electron transport carrier through the thylakoid membrane (thylakoids are present in chloroplasts), and is present in the photosystem II in plants and other photosynthetic organisms. PSII produces the chemical energy as ATP.
PQ is reduced when it accepts electrons from PSII, and then it delivers them to plastocyanin, that is a water-soluble electron carrier in the cytochrome b6f complex.