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Alex17521 [72]
3 years ago
15

When a certain capacitor carries charge of magnitude Q on each of its plates, it stores energy Ep. In order to store twice as mu

ch energy, how much charge should it have on its plates
Physics
1 answer:
padilas [110]3 years ago
3 0
<h2>Answer:</h2>

2Q

<h2>Explanation:</h2>

When a capacitor carries some certain charge, the energy stored in the capacitor is its electric potential energy E. The magnitude of this potential energy is given by;

E  = \frac{1}{2}qV            ------------(i)

Where;

q = charge between the plates of the capacitor

V = potential difference between the plates of the capacitor

From the question;

q = Q

E = Ep

Therefore, equation (i) becomes;

Ep = \frac{1}{2} QV              ----------------(ii)

Make V subject of the formula in equation (ii)

V = \frac{2E_{p}}{Q}

Now, when the energy is doubled i.e E = 2Ep, equation (i) becomes;

2Ep = \frac{1}{2}qV

Substitute the value of V into the equation above;

2Ep = \frac{1}{2}(q *\frac{2E_{p}}{Q})

Solve for q;

2E_{p} = \frac{2qE_p}{2Q}

2E_{p} = \frac{qE_p}{Q}

q = 2Q

Therefore, the charge, when the energy stored is twice the originally stored energy, is twice the original charge. i.e 2Q

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