Answer:
El valor de la fuerza que debe ejercer la persona C debe ser de -2 para que la caja esté en equilibrio físico.
Explanation:
Si la caja debe hallarse en equilibrio físico, entonces se debe satisfacer la siguiente ecuación:
(1)
Si sabemos que y , entonces el valor de la fuerza que debe ejercer la persona C debe ser:
El valor de la fuerza que debe ejercer la persona C debe ser de -2 para que la caja esté en equilibrio físico.
Answer:
Explanation:
v = 50 km / h
= 13.89 m /s
When a vehicle runs on a circular path , it is static friction which prevents it from getting overturned .
static friction = μs mg
centripetal force = m v² / R
m v² / R = μs mg
R = v² / μs x g
= 13.89² / .7 x 9.8
= 28.12 m .
B. it accelerates at a rate of 9.8m/s/
Acceleration = force / mass.
A = 100/50 = 2 m/s^2 .
(a) Centripetal: , tangential:
The radius of the track (which is the distance of the car from the centre of the circular path) is
r = 0.30 km = 300 m
The angular acceleration is
We can find the angular velocity of the car after half of a lap using the equivalent of the SUVAT equation for rotational motions:
where
since the car starts from rest
is the angular displacement after half a lap
Solving for ,
Now we can find the centripetal acceleration with the formula:
while the tangential acceleration is simply given by
(b) The mass of the car is not given, so it is not possible to find the forces.