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swat32
3 years ago
14

I forgot how to do this so please help me.

Mathematics
1 answer:
Makovka662 [10]3 years ago
7 0

Answer:

Draw a straight line that goes through the point (0,4) and (20,0)

Step-by-step explanation:

The y-intercept is equal to 4, since the function is already in y=mx+b form, where b is the y-intercept.

To find the x-intercept, we substitute 0 into y or in this case the f(x).

0 = -1/5 (x) + 4

1/5 x = 4

x = 20

The x-intercept is 20.

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You are dealt one card from 52 card deck. Find the possibility that you are dealt a heart or a picture card
PIT_PIT [208]

Answer:

<h2>11/26</h2>

Step-by-step explanation:

Since we have 13 heart card then

p(heart) = 13/52

Since we have 12 picture card then

p(picture) = 12/52

Since we have 3 heart and picture (at the same time) card then

p(heart∩picture) = 3/52

finally,

the possibility that you are dealt a heart or a picture card = p(heart or picture)

p(heart or picture) = 13/52 + 12/52 - 3/52 = 22/52

7 0
4 years ago
In the figure, the measure of angle 7 is 57°. What is the measure of angle 8?
pochemuha
Angle (6) + Angle (7) = 180

Angle (6) + 57 = 180

Angle (6) = 180 - 57

Angle (6) = 123

------------

Angle (6) = Angle (8)

-----------

Therefore:

Angle (8) = 123 degrees
5 0
3 years ago
Read 2 more answers
19632 divided by 218<br><br><br>please help
Anton [14]
<span>90.0550458716 is the answer</span>
3 0
3 years ago
Read 2 more answers
What is the equation of the circle with center (0, 1) and a radius of 10?
victus00 [196]

<u>Answer:  </u>

The equation of the circle with center (0, 1) and a radius of 10 is \bold{x^{2} + y^{2} - 2y-99 = 0}

<u>Solution: </u>

Equation of circle whose center (h, k) and radius r is given as,

(x-h)^{2} + (y-k)^{2} = r^{2} ---- eqn 1

From question, given that the circle has radius 10 and center (0, 1). We have to find the equation of the circle.

Hence we get, h = 0 ; k = 1; r = 10

By using eqn 1, the equation of circle whose center (0, 1) and radius 10 is given as

(x-0)^{2} + (y - 1)^{2} = 10^{2}

On Simplifying we get

x^{2} + (y-1)^{2} = 10^{2}

Expand (y-1)^{2} using the formula (a-b)^{2} = a^{2} - 2ab + b^{2}

x^{2} + y^{2} - 2y + 1 = 10^{2}

x^{2} + y^{2} - 2y + 1 = 100

x^{2} + y^{2} - 2y + 1-100 = 0

x^{2} + y^{2}- 2y- 99 = 0

Hence equation of the circle with center (0, 1) and a radius of 10 is  \bold{x^{2}+y^{2}-2 y-99=0}

3 0
3 years ago
5. Find the equation of the line that goes through the points (4,7) and (-2,-5)
Lelechka [254]

Answer:

equation= y-y¹=m(x-x¹)

where m= gradient or slope

slope = <u>y²-y¹</u>

x²-x¹

= -<u>5-7</u>

-2-4

<u>-</u><u>1</u><u>2</u>

-6

= 2

equation= y-7=2(x-4)

y-7=2x-8

y= 2x-8+7

y=2x-1

8 0
2 years ago
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