A, who travels 4 miles an hour starts from a certain place 2 hours in advance of B, who travels 5
1 answer:
It will take B 8 hours to travel in order to overtake A.
The relationship among the distance, time and speed can be expressed by using the relation.
In this kind of ratio relation, it is pertinent to understand that, the rise in a variable cause a decrease in the other, where the third variable is constant.
Here:
- as speed (v) rises;
- time (t) decreases, and
- distance (d) is constant
From the given relation:
- Distance = speed × time
So, we can have a table expressing the parameters given in the question as follows:
v t d
A 4 t+2 4t + 8
B 5 t 5t
Equating both distance together, we have:
4t + 8 = 5t
collecting like terms, we have:
4t - 5t = -8
t = 8 hours
Therefore, we can conclude that it will take B 8 hours to travel in order to overtake A.
Learn more about distance, time and speed here:
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Answer
Find out the which system of equations could be used to determine the number of hours charged at the day rate (d) and at the night rate (n) .
To proof
As given in the question
Let us assume that the number of hours charged at the day rate = d
Let us assume that the number of hours charged at the night rate = n
An online data base charges $25 an hour during the day and $12.50 an hour at night. If a research company paid $250 for 12 hours of use.
Total working hour in a company including day and night be 12 hours .
than the equation become in the form
d + n = 12
also
An online data base charges $25 an hour during the day
$12.50 an hour at night.
If a research company paid $250 for 12 hours of use.
than the equation becomes
25d + 12.50n = 250
than the two equation are
d + n = 12 , 25d + 12.50n = 250
multiply first by 25 and subtracted from 25d + 12.50n = 250
25d - 25d + 12.50n - 25n = 250 - 300
12.5 n = 50
n = 4hours
put this in the d + n = 12
d + 4 =12
d = 12-4
d = 8 hours
Therefore the number of hours charged at the day rate is 8 hours and at the night rate is 4hours .
Hence proved