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2 years ago

Describe the transformations that map A onto the point A”.

Mathematics

1 answer:

dexar [7]2 years ago

6 0

Answer:

Step-by-step explanation:

(x, y) -----> (x + 4, y - 1)

Adding 4 to the x means you move right 4. Subtracting 1 from the y means you move down one.

The next transformation (-(x + 4), y - 1)

If you look at the x coordinate and the transformation that is being applied

(-(x+4) that negative means you are taking the opposite of the x coordinate.

When you take the opposite of the x coordinate, it means you reflect it over the y axis.

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Answer:

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Step-by-step explanation:

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Read 2 more answers

Find a closed-form solution to the integral equation y(x) = 3 + Z x e dt ty(t) , x > 0. In other words, express y(x) as a fun

MrMuchimi

Answer:

$y{x} = \sqrt{7+2Inx}$

Step-by-step explanation:

$y(x)= 3 + \int\limits^x_e {dx}/ \, ty(t) , x>0}$

Let say; By y(x)= y(e)

we have;

$y(e)= 3 + \int\limits^e_e {dt}/ \, ty= 3+0$

Using Fundamental Theorem of Calculus and differentiating by Lebiniz Rule:

$y^{1} (x) = 0 + 1/ xy$

$y^{1} = 1/xy$

dy/dx = 1/xy

$\int\limits {y} \, dxy = \int\limits \, dx/x$

$y^{2}/2 Inx + C$

RECALL: y(e) = 3

$(3)^{2} / 2 = In (e) + C$

$\frac{9}{2} =In(e)+C$

$\frac{9}{2} - 1 = C$

$\frac{7}{2} = C$

$y^{2} / 2 = In x +C$

$y^{2} / 2 = In x +7/2$

MULTIPLYING BOTH SIDE BY 2 , TO ELIMINATE THE DENOMINATOR, WE HAVE;

$y^{2} = {7+2Inx}$

$y{x} = \sqrt{7+2Inx}$

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3 years ago