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Nesterboy [21]
2 years ago
14

Describe the transformations that map A onto the point A”.

Mathematics
1 answer:
dexar [7]2 years ago
6 0

Answer:

A

Step-by-step explanation:

(x, y) -----> (x + 4, y - 1)

Adding 4 to the x means you move right 4.  Subtracting 1 from the y means you move down one.

The next transformation (-(x + 4), y - 1)

If you look at the x coordinate and the transformation that is being applied

(-(x+4) that negative means you are taking the opposite of the x coordinate.

When you take the opposite of the x coordinate, it means you reflect it over the y axis.

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Whats 16 = k/11<br>and v/8=2
Dvinal [7]
16= \frac{k}{11} &#10;\\16*11=k&#10;\\k=176&#10;&#10;

\frac{v}{8} =2&#10;\\v=8*2&#10;\\v=16
6 0
3 years ago
Let the following sample of 8 observations be drawn from a normal population with unknown mean and standard deviation:
Vikentia [17]

Answer:

a

   \= x  = 18.5  ,  \sigma =  5.15

b

 15.505 < \mu <  21.495

c

 14.93 < \mu <  22.069

Step-by-step explanation:

From the question we are are told that

    The  sample data is  21, 14, 13, 24, 17, 22, 25, 12

     The sample size is  n  = 8

Generally the ample mean is evaluated as

        \= x  =  \frac{\sum x  }{n}

        \= x  =  \frac{  21 + 14 + 13 + 24 + 17 + 22+ 25 + 12  }{8}

         \= x  = 18.5

Generally the standard deviation is mathematically evaluated as

         \sigma =  \sqrt{\frac{\sum (x- \=x )^2}{n}}

\sigma =  \sqrt{\frac{\sum ((21 - 18.5)^2 + (14-18.5)^2+ (13-18.5)^2+ (24-18.5)^2+ (17-18.5)^2+ (22-18.5)^2+ (25-18.5)^2+ (12 -18.5)^2 )}{8}}

\sigma =  5.15

considering part b

Given that the confidence level is  90% then the significance level is evaluated as

         \alpha  =  100-90

         \alpha  = 10\%

         \alpha  = 0.10

Next we obtain the critical value of  \frac{ \alpha }{2}  from the normal distribution table the value is  

     Z_{\frac{ \alpha }{2} }  =  1.645

The margin of error is mathematically represented as

      E =  Z_{\frac{ \alpha }{2} } *  \frac{\sigma }{\sqrt{n} }

=>    E =1.645  *  \frac{5.15 }{\sqrt{8} }

=>     E =  2.995

The 90% confidence interval is evaluated as

       \= x  -  E < \mu <  \= x +  E

substituting values

       18.5 -  2.995 < \mu <  18.5 +  2.995

       15.505 < \mu <  21.495

considering part c

Given that the confidence level is  95% then the significance level is evaluated as

         \alpha  =  100-95

         \alpha  = 5\%

         \alpha  = 0.05

Next we obtain the critical value of  \frac{ \alpha }{2}  from the normal distribution table the value is  

     Z_{\frac{ \alpha }{2} }  =  1.96

The margin of error is mathematically represented as

      E =  Z_{\frac{ \alpha }{2} } *  \frac{\sigma }{\sqrt{n} }

=>    E =1.96  *  \frac{5.15 }{\sqrt{8} }

=>     E = 3.569

The 95% confidence interval is evaluated as

       \= x  -  E < \mu <  \= x +  E

substituting values

       18.5 - 3.569 < \mu <  18.5 +  3.569

       14.93 < \mu <  22.069

8 0
3 years ago
5 quarters weigh approximately 1 ounce. How many ounceswould you expect a collection of quarters worth $15 to weigh?
PSYCHO15rus [73]

5 quarters =1.25$

15$÷1.25$=12

then 15$ in quaters would weigh 12 ounces

8 0
2 years ago
How much food can this container hold? Express your answer in terms of pie. question 5 in i-ready
Scilla [17]

Answer:

jfcsdifp

Step-by-step explanation:

5 0
3 years ago
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At which points are the equations y=x^2+3x+2 and y=2x+3 approximately equal
ASHA 777 [7]

so x^2 + 3x + 2 = 2x+3

or x^2 + x  = 1


After that just use the a quadratic equation formula

6 0
3 years ago
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