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3 years ago

Can you help me understand this question? And what are they looking for? I really need help please...

Mathematics

1 answer:

castortr0y [4]3 years ago

6 0

The question is asking you weather you agree or not. I would say not because there are more black pens then red, therefore if someone went to grab a pen not looking there's a higher chance of it being black instead of red. Does that make sense?

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A bag of rice weighs 2.5 pounds. How many ounces is that?

blondinia [14]

40 ounces is 2.5 pounds because each pound is 16 ounces

3 0

3 years ago

Read 2 more answers

Given the equation y = -3x +1/2 , what is the y-intercept?

pychu [463]

y intercept = 1/2

<u>Step-by-step explanation:</u>

Step 1:

Formula y=mx+b in Slope Intercept form( whereas m= slope of the given equation, b= y intercept)

Step 2:

Comparing the given equation y = -3x + 1/2

we get m=-3(Slope) and y-intercept b=1/2

3 0

2 years ago

What is the equation of the line in slope-intercept form with slope -3/2 and y-intercept -5?

V125BC [204]

About Slope Intercept Form:

y = mx + b
m represents the slope
b represents the y-intercept or AKA the starting point

ABOUT PROBLEM:

Since -3/2 is the slope, it represents m in Slope Intercept Form
Since -5 is the y-intercept, it represents b in Slope Intrecept Form

y = mx + b

y = -3/2x + -5 --- IN Slope Intercept Form

Hope this helps you!!! :)

5 0

3 years ago

Question 4

Elanso [62]

Answer:

a $A = 30 + 0.45 n$

b $A = 90.3$

c 0 customers

Step-by-step explanation:

Given

$Base\ Amount = 30$

$Rate = 0.45$ per customer

Solving (a): Amount (A) on n customers

This is calculated as:

$A = Base\ Amount + Rate * n$

$A = 30 + 0.45 * n$

$A = 30 + 0.45 n$

Solving (b): Amount on 134 customers

In this case: n = 134

So:

$A = 30 + 0.45 * 134$

$A = 30 + 60.3$

$A = 90.3$

Solving (c): Customers at noon.

At noon, the amount is 30.

So:

$A = 30 + 0.45 n$

$30 = 30 + 0.45n$

Collect like terms

$0.45n = 30 - 30$

$0.45n =0$

$n = 0$

6 0

2 years ago

A statistician uses Chebyshev's Theorem to estimate that at least 15 % of a population lies between the values 9 and 20. Use thi

rjkz [21]

Answer:

\mu = 14.5\\

\sigma = 5.071\\

k = 1.084

Step-by-step explanation:

given that a statistician uses Chebyshev's Theorem to estimate that at least 15 % of a population lies between the values 9 and 20.

i.e. his findings with respect to probability are

$P(9$

Recall Chebyshev's inequality that

$P(|X-\mu |\geq k\sigma )\leq {\frac {1}{k^{2}}}\\P(|X-\mu |\leq k\sigma )\geq 1-{\frac {1}{k^{2}}}\\$

Comparing with the Ii equation which is appropriate here we find that

$\mu =14.5$

Next what we find is

$k\sigma = 5.5\\1-\frac{1}{k^2} =0.15\\\frac{1}{k^2}=0.85\\k=1.084\\1.084 (\sigma) = 5.5\\\sigma = 5.071$

Thus from the given information we find that

$\mu = 14.5\\\sigma = 5.071\\k = 1.084$

5 0

3 years ago