→ a
the equation is y = mx ( where m is the slope / constant of variation )
calculate m using the gradient formula
m = ( y₂ - y₁ ) / (x₂ - x₁ )
with (x₁, y₁) = (0, 0 ) and (x₂, y₂ ) = (4, 1) ← 2 points on the line
m =
= 
You have to find out what x is because x is an imaginary number
Answer:
Step-by-step explanation:
Given that there is a function of x,

Let us find first and second derivative for f(x)

When f'(x) =0 we have tanx = 1 and hence
a) f'(x) >0 for I and III quadrant
Hence increasing in 
and decreasing in 


Hence f has a maxima at x = pi/4 and minima at x = 3pi/4
b) Maximum value = 
Minimum value = 
c)
f"(x) =0 gives tanx =-1

are points of inflection.
concave up in (3pi/4,7pi/4)
and concave down in (0,3pi/4)U(7pi/4,2pi)
Answer:
The first one
Step-by-step explanation: