<span> 80/-40=-40/20=-2,
the sequence: 80, -40, 20 is a geometric sequence
its general formula is Vn+1 = q Vn, where q= -2,
if we put </span>Vn+1 = f(x)
<span> Vn = x
so we have f(x)= -2x so the graph that represents the sequence is graph of linear equation
</span>
The area of an equilateral triangle of side "s" is s^2*sqrt(3)/4. So the volume of the slices in your problem is
(x - x^2)^2 * sqrt(3)/4.
Integrating from x = 0 to x = 1, we have
[(1/3)x^3 - (1/2)x^4 + (1/5)x^5]*sqrt(3)/4
= (1/30)*sqrt(3)/4 = sqrt(3)/120 = about 0.0144.
Since this seems quite small, it makes sense to ask what the base area might be...integral from 0 to 1 of (x - x^2) dx = (1/2) - (1/3) = 1/6. Yes, OK, the max height of the triangles occurs where x - x^2 = 1/4, and most of the triangles are quite a bit shorter...
Answer:
Step-by-step explanation:
Parallel lines have the same slope. The slope of the given line is 3. The easy way to do this, the one that uses our logical brains as opposed to our mathematical brain, tells us that since there is only one choice that has a given slope of 3, that is the one that we want. The second choice down is the only one that has a slope of 3.
Mathematically,
and
and
so
y = 3x - 7 (the second choice)