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weqwewe [10]
2 years ago
10

Kay is running a 13.5 km race. If she runs at a rate of 8 2/5 km/he for 1.5 hours, how many kilometers will she have left to run

to finish the race?
Mathematics
1 answer:
Monica [59]2 years ago
7 0

The number of kilometers she will have left to run to finish the race is 0.9 km.

<u>Given the following data:</u>

  • Total distance = 13.5 km
  • Speed = 8\frac{2}{5} \;km/hr
  • Time = 1.5 hours

To determine the number of kilometers she will have left to run to finish the race:

First of all, we would calculate the distance she has covered by using this formula;

Distance = speed \times time\\\\Distance = 8\frac{2}{5} \times 1.5\\\\Distance = \frac{42}{5} \times \frac{3}{2} \\\\Distance = \frac{63}{5}

Distance = 12.6 meters.

<u>For the </u><u>distance left</u><u>:</u>

Distance\;left = Total\;distance - Distance\;covered\\\\Distance\;left =13.5 -12.6

Distance left = 0.9 km.

Learn more about distance here: brainly.com/question/10545161

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How to reduce into simpler terms.?
Sveta_85 [38]

Answer:

The simplest form of the fraction \frac{45}{100}  is  \frac{9}{20}.

i.e.

\frac{45}{100}=\frac{9}{20}

Step-by-step explanation:

Here are some simple observations regarding how to reduce a fraction into simpler terms:

  • A fraction is reduced to lowest or simplest terms by finding an equivalent fraction in which the numerator and denominator are as small as possible.
  • In order to reduce a fraction to lowest or simplest terms, divide the numerator and denominator by their (GCF). Note that (GCF) is also called Greatest Common Factor .

So, lets take a sample fraction and reduce into simpler terms.

Considering the fraction

\frac{45}{100}

\mathrm{Find\:a\:common\:factor\:of\:}45\mathrm{\:and\:}100\mathrm{\:in\:order\:to\:cancel\:it\:out}

\mathrm{Greatest\:Common\:Divisor\:of\:}45,\:100:\quad 5

\mathrm{Factor\:out\:}5\mathrm{\:from\:the\:numerator\:and\:the\:denominator}

45=5\cdot \:9\mathrm{,\:\quad }100=5\cdot \:20

so

\frac{45}{100}=\frac{5\cdot \:\:9}{5\cdot \:\:20}

\mathrm{Cancel\:the\:common\:factor:}\:5

     =\frac{9}{20}

Therefore, the simplest form of the fraction \frac{45}{100}  is  \frac{9}{20}.

i.e.

\frac{45}{100}=\frac{9}{20}

4 0
3 years ago
(14.14) larry reads that 1 out of 6 eggs contains salmonella bacteria. so he never uses more than 5 eggs in cooking. if eggs do
melomori [17]

we know that

The probability that "at least one" is the probability of exactly one, exactly 2, exactly 3, 4 and 5 contain salmonella.

The easiest way to solve this is to recognise that "at least one" is ALL 100% of the possibilities EXCEPT that none have salmonella.

If the probability that any one egg has 1/6 chance of salmonella

then

the probability that any one egg will not have salmonella = 5/6.

Therefore

for all 5 to not have salmonella


= (5/6)^5 = 3125 / 7776

= 0.401877 = 0.40 to 2 decimal places


REMEMBER this is the probability that NONE have salmonella


Therefore

the probability that at least one does = 1 - 0.40

= 0.60


the answer is

0.60 or 60%

6 0
3 years ago
Subtract one-third from 8 times b
steposvetlana [31]

i think the answer is 1/3 from 8x 6 =-46.7 i think

6 0
3 years ago
if 2 people answered your question and they were both right but only one of them explained they answer who should I give brainli
lakkis [162]
The person who explained the answer because you can see how they got the answer or the evidence they used to get the answer
5 0
3 years ago
Please help thank you very much
-BARSIC- [3]
Hello!

The answer is 34°

Hope this helps!
7 0
3 years ago
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