Yes it does ! Uh huh. Right you are. Truer words are seldom written.
You have quoted the law quite accurately but also incompletely.
Do you have a question to ask ?
Answer:
Explanation:
A ) Distance between two adjacent anti-node will be equal to distance between two adjacent nodes . So the required distance is 15 cm .
B ) wave-length, amplitude, and speed of the two traveling waves that form this pattern are as follows
wave length = same as wave length of wave pattern formed. so it is 30 cm
amplitude = 1/2 the amplitude of wave pattern formed so it is .850 / 2 = .425 cm
Speed = frequency x wavelength ( frequency = 1 / time period )
= 1 / .075) x 30 cm
400 cm / m
C ) maximum speed
= ω A
= (2π / T) x A
= 2 X 3.14 x .85 / .075 cm / s
= 71.17 cm / s
minimum speed is zero.
D ) The shortest distance along the string between a node and an antinode
= Wavelength / 4
= 30 / 4
= 7.5 cm
The speed of the brick dropped by the builder as it hits the ground is 17.32m/s.
Given the data in the question;
Since the brick was initially at rest before it was dropped,
- Initial Velocity;

- Height from which it has dropped;

- Gravitational field strength;

Final speed of brick as it hits the ground; 
<h3>Velocity</h3>
velocity is simply the same as the speed at which a particle or object moves. It is the rate of change of position of an object or particle with respect to time. As expressed in the Third Equation of Motion:

Where v is final velocity, u is initial velocity, h is its height or distance from ground and g is gravitational field strength.
To determine the speed of the brick as it hits the ground, we substitute our giving values into the expression above.

Therefore, the speed of the brick dropped by the builder as it hits the ground is 17.32m/s.
Learn more about equations of motion: brainly.com/question/18486505