Say you were at mission control on

Physics

1 answer:

Ad libitum [116K]2 years ago

4 0

Answer:

because mars is far

Explanation:

so if he shouts louder than he will hear it quicker

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There is evidence that elephants communicate via infrasound, generating rumbling vocalizations as low as 14 Hz that can travel u

amid [387]

Answer:

$L = 96.2 dB$

Explanation:

As we know that the level of intensity is given as

$\beta = 10Log(\frac{I}{I_o})$

here we know

$\beta = 104 dB$

$104 = 10Log(\frac{I}{10^{-12}})$

$I = 0.025 W/m^2$

now the sound is travelling in all possible directions so we have

$\frac{I_1}{I_2} = \frac{r_2^2}{r_1^2}$

$\frac{0.025}{I_2} = \frac{10^2}{4.1^2}$

$I_2 = 4.2 \times 10^{-3} W/m^2$

now for level of sound we have

$L = 10Log(\frac{4.2 \times 10^{-3}}{10^{-12}})$

$L = 96.2 dB$

5 0

3 years ago

If earth increase the distance from the sun, what will happen to the period of orbi t(the time it takes to complete one revoluti

Mandarinka [93]

The period of the orbit would increase as well

Explanation:

We can answer this question by applying Kepler's third law, which states that:

"The square of the orbital period of a planet around the Sun is proportional to the cube of the semi-major axis of its orbit"

Mathematically,

$\frac{T^2}{a^3}=const.$

Where

T is the orbital period

a is the semi-major axis of the orbit

In this problem, the question asks what happens if the distance of the Earth from the Sun increases. Increasing this distance means increasing the semi-major axis of the orbit, $a$ : but as we saw from the previous equation, the orbital period of the Earth is proportional to $a$ , therefore as $a$ increases, T increases as well.