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ArbitrLikvidat [17]
4 years ago
8

Gaseous helium is in thermal equilibrium with liquid helium at 6.4 K. The mass of a helium atom is 6.65 × 10−27 kg and Boltzmann

’s constant is 1.38066 × 10−23 J/K. Determine the most probable speed of a helium atom. Answer in units of m/s.
Physics
1 answer:
chubhunter [2.5K]4 years ago
4 0

Answer:

162.78 m/s is the most probable speed of a helium atom.

Explanation:

The most probable speed:

v_{mp}=\sqrt{\frac{2K_bT}{m}}

K_b= Boltzmann’s constant =1.38066\times 10^{-23} J/K

T = temperature of the gas

m = mass of the gas particle.

Given, m = 6.65\times 10^{-27} kg

T = 6.4 K

Substituting all the given values :

v_{mp}=\sqrt{\frac{2\times 1.38066\times 10^{-23} J/K\times 6.4 K}{6.65\times 10^{-27} kg}}

v_{mp}=162.78 m/s

162.78 m/s is the most probable speed of a helium atom.

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2. 3600 m.

Explanation:

The following data were obtained from the question:

Initial velocity (u) = 0

Acceleration (a) = 0.5 m/s²

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1. Determination of the velocity at the end of 2 minutes.

Initial velocity (u) = 0

Acceleration (a) = 0.5 m/s²

Time (t) = 2 mins = 2 x 60 = 120 secs

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v = u + at

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v = 60 m/s

Therefore, the velocity at the end of 2 minutes is 60 m/s.

2. Determination of the distance travelled.

Initial velocity (u) = 0

Acceleration (a) = 0.5 m/s²

Final velocity (v) = 60 m/s

Distance travelled (s) =..?

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6 0
3 years ago
.A 100.0-W lightbulb is 22 percent efficient. This means that 22 percent of the electrical energy is transformed to radiant ener
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Answer:

Explanation:

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a )

So , electrical energy is transformed to radiant energy per second

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b )

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energy transformed in one minute = 78 x 60  J

= 4680  J

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