Answer:
Check attachment for better understanding
Explanation:
Given that,
Current in wire I =2.2A
Capacitor plate dimension is 2cm by 2cm
s=2cm=2/100 = 0.02m
Rate at which electric field Is changing dE/dt?
The current in the wires must also be the displacement current in the capacitor. We find the rate at which the electric field is changing from
ID = ε0•A•dE/dt
Where ε0 is a constant
ε0= 8.85×10^-12C²/Nm²
Area of the square plate is
A =s² =0.02² = 0.0004m²
Then,
Make dE/dt the subject of formula
dE/dt = ID/ε0A
dE/dt = 2.2 / (8.85×10^-12 ×4×10^-4)
dE/dt = 6.215×10^14 V/m-s
Or
dE/dt = 6.215×10^14 N/C.s
The rate at which the electric field is changing between the plates is 6.215×10^14 N/C.s
I answered the question but it got deleted?? why?
Answer:
because the force of water coming out of the hose needs a stardy flow
Explanation:
Answer:
a = 616850.28 m/s²
Explanation:
Given that,
The radius of the neutron star, r = 10 Km
= 10,000 m
The time period of the neutron star, T = 0.8 s
The centripetal acceleration is given by the formula,
a = v²/r
The linear velocity is given by the relation,
v = rω
The time taken to complete one complete rotation is given by the relation
T = 2π /ω
Where,
ω = 2π / T
Substituting v and ω into the equation for centripetal acceleration. It becomes
a = 4π²r/T²
Substituting the given values in the above equation
a = 4π² x 10000 / 0.8²
= 616850.28 m/s²
Hence, the centripetal acceleration of this person is, a = 616850.28 m/s²
