I will try to define the net problem, without the intermediate message between the message as:
<em>An air-filled toroidal solenoid has a mean radius of 15.5 cm and a cross-sectional area of 4.95 cm2 . When the current is 12.5 A , the energy stored is 0.390 J . </em>
<em>Part A: How many turns does the winding have?</em>
To solve the problem it is necessary to apply the concepts related to the storage of energy in an inductor and how it is possible to calculate from the inductance the number of turns of the system.
By definition we know that the energy stored in an inductor is given by,
Where,
L = Inductance
I = Current
In this way, clearing the Inductance in the previously given equation we have to
In a system the inductance is given by
Where l represents the length, however as we deal with the perimeter of a circle we have,
Replacing our values we have
Re-arrange to find N,
Therefore the winding have 2211turns
Answer:
The wavelength of the emitted photon is 413.6 nm
Explanation:
Given;
energy of the emitted photon, E = 3 eV = 3 x 1.602 x 10⁻¹⁹ J
speed of light, c = 3 x 10⁸ m/s
The energy of the emitted photon is given by;
E = hf
where;
h is Planck's constant = 6.626 x 10⁻³⁴ J/s
f is the frequency of the light = c / λ
λ is the wavelength
Therefore, the wavelength of the emitted photon is 413.6 nm
Explanation:
K.E. of marble 1 = (1/2) × 0.2 × (22/0.8) ^2
= 0.1 × 756.25
= 75.625
K.E. of marble 2 = (1/2) × 1.2 × (26/0.8)^2
= 0.6 × 1056.25
= 633.75
I would think it is B I am not certain though..
Answer:
5.1m
Explanation:
Use the fourth key equation of accelerated motion
vf^2=vi^2+2aΔd
we know vf is = 0 because that is when the ball reaches it's peak (not going up anymore)
0=vi^2+2aΔd
and we can rearrange for Δd, which is what you need
-vi^2=2aΔd
Δd = -vi^2/2a
Now we can plug in the values
Δd = -vi^2/2a
Δd = -(10m/s)^2/2(-9.8)
Δd = -100/-18.6
Δd = 5.10m