Scenario:
1 answer:
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It sounds as though the two people are standing in front of the boat on opposite sides of it, so that they both make an angle of 30.0° with the axis of the boat, as in the attached free body diagram (ignoring the force of buoyancy and the weight of the boat).
By Newton's second law, the net vertical force is
∑ <em>F</em> = <em>P</em>₁ sin(60.0°) + <em>P</em>₂ sin(120.0°) - <em>R</em> = 0
where upward is positive and downward is negative, and the right side is 0 because the boat moves with constant velocity and thus zero acceleration.
We're told that <em>P</em>₁ = <em>P</em>₂ = 600 N, and we know sin(60°) = sin(120°), so the above reduces to
<em>R</em> = 2 <em>P</em> sin(60.0°) = 2 (600 N) sin(60.0°) ≈ 1040 N
The frictional force required is 9000 N
Explanation:
In order to keep the car in the turn in circular motion without sliding, the frictional force must provide the centripetal force necessary for the circular motion.
Therefore, we can write:
where the term on the left is the frictional force while the term on the right is the centripetal force, and where:
m is the mass of the car
v is its speed
r is the radius of the curve
For the car in this turn, we have
m = 1000 kg
v = 30 m/s
(since the diameter is 0.20 km, the radius is half that value)
And substituting, we find
Learn more about friction:
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