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Alona [7]
3 years ago
5

A train travelling at 20m/s undergoes a uniform deceleration of 2m/s2 when brakes are applied.. calculate the time taken to come

to rest and distance travel from the place where the brakes were applied ​
Physics
1 answer:
VLD [36.1K]3 years ago
6 0

Answer:

a) 10 seconds

b) 100 meters

Explanation:

<u>Accelerated Motion </u>

If an object is moving at contant speed, we know it has zero net force applied. As soon as an unbalanced force appears, the object accelerates (positive or negative) depending on the direction of the force with respect to movement. The speed of an object subject to acceleration is given by

v_f=v_o+at

The distance traveled is given by

\displaystyle x=v_ot+\frac{at^2}{2}

a)

Our train is travelling at 20m/s when it decelerates at -2\ m/s^2 (negative for it's against movement). If nothing else happens, it will eventually stop (v_f=0). We can compute the time at which it happens :

\displaystyle t=\frac{v_f-v_o}{a}

Knowing\ v_f=0

\displaystyle t=\frac{-20}{-2}=10\ sec

b)

The distance traveled is

\displaystyle x=v_ot+\frac{at^2}{2}

\displaystyle x=(20)(10)-\frac{2(10)^2}{2}

\displaystyle x=100\ m

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