HELP Please Help Me!!!! I need to get this done and I can’t figure out this problem!!!
1 answer:
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Answer:
a) YES. Repeating decimal
b) YES. Repeating decimal
c) NO. Decimal neither terminates nor repeats
d) YES. Terminating decimal
Step-by-step explanation:
Any rational number can be written as a fraction, that is, a division of integers.
a) The number has a repetitive period of 54. It can be expressed as a fraction because its decimal are repeating forever
b) The number 0.16666... (expressed as a repeating 6) can also be converted to a fraction because it's a repeating decimal
c) The number 0.5473... cannot be expressed as a fraction because the ellipsis (...) means the decimals continue with no limit and no pattern can be found (no repetitive decimal)
d) The number 0.378 can be easily expressed as a fraction because it has a finite number of decimals (no ellipsis) or a terminating decimal
The equations are
,
The graphs of the solutions (x, y) of these equations are 2 parabolas, since the right hand side expressions are polynomials of degree 2.
The solution/s of the system are the x-coordinates of the point/s of intersection of the parabolas.
The solutions of the first equation form a parabola looking downwards (since the coefficient of x^2 is -), and the second, a parabola opening upwards (since the coefficient of x^2 is +).
We can draw both parabolas, but to find the solution we still need to solve the system algebraically.
The algebraic solution of the system is:
, so
the solutions are x=-1 and x=1.
The graph of the system is drawn using desmos.com
If we are allowed to use a graphic calculator, we can draw both graphs and point at the solution.
The graphs of the solutions (x, y) of these equations are 2 parabolas, since the right hand side expressions are polynomials of degree 2.
The solution/s of the system are the x-coordinates of the point/s of intersection of the parabolas.
The solutions of the first equation form a parabola looking downwards (since the coefficient of x^2 is -), and the second, a parabola opening upwards (since the coefficient of x^2 is +).
We can draw both parabolas, but to find the solution we still need to solve the system algebraically.
The algebraic solution of the system is:
the solutions are x=-1 and x=1.
The graph of the system is drawn using desmos.com
If we are allowed to use a graphic calculator, we can draw both graphs and point at the solution.