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2 years ago

HELP Please Help Me!!!! I need to get this done and I can’t figure out this problem!!!

Mathematics

1 answer:

zysi [14]2 years ago

5 0

Answer:

3, 15/7, 9/7, 3/7, -3/7, -9/7

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I think its the second one but I'm not sure..

yuradex [85]

Yes it’s correct. You just need to plug each of the x and y values to see if they satisfy the equation.

7 0

3 years ago

Hello!

max2010maxim [7]

Let O be the point of intersection of diagonals.

Consider triangles FOE and EOD:
FO = OD, ∠FOE = ∠EOD and OE is a common side ⇒
triangles FOE and EOD are congruent.

In congruent triangles all corresponding sides and are congruent ⇒
EF = DE = 6

6 0

3 years ago

2,5, 25/2, ... find the 10th term

notka56 [123]

Answer:

The $10^{th}$ term of the given sequence

$t_{10} = \frac{5^{9} }{2^{8} }$

Step-by-step explanation:

Step(i):-

Given sequence 2 , 5, $\frac{25}{2}$

First term a = 2

The difference of given geometric sequence

$d = \frac{r_{2} }{r_{1} } = \frac{5}{2}$

Step(ii):-

The $n^{th}$ term of the given sequence

$t_{n} = ar^{n-1}$

The $10^{th}$ term of the given sequence

$t_{10} = (2)(\frac{5}{2} )^{10-1}$

$t_{10} = (2)(\frac{5}{2} )^{9}= \frac{5^{9} }{2^{8} }$

8 0

3 years ago

What is the missing part of the solution?

hoa [83]

9514 1404 393

Answer:

6.64

Step-by-step explanation:

Perhaps you have ...

$3.4\times10^{-20}+5.4\times10^{-19}+9\times10^{-20}=\underline{\ \ \ \ }\times10^{-19}\\\\=(0.34+5.40+0.90)\times10^{-19}=\boxed{6.64}\times10^{-19}$