SOLUTION:
PQR is a right-angle triangle.
Therefore, to solve this problem, we will use Pythagoras theorem which is only applicable to right-angle triangles.
Pythagoras theorem is as displayed below:
a^2 + b^2 = c^2
Where c = hypotenuse of right-angle triangle
Where a and b = other two sides of right-angle triangle
Now we will simply substitute the values from the problem into Pythagoras theorem in order to obtain the length of QR.
c = PQ = 16cm
a = PR = 8cm
b = QR = ?
a^2 + b^2 = c^2
( 8 )^2 + b^2 = ( 16 )^2
64 + b^2 = 256
b^2 = 256 - 64
b^2 = 192
b = square root of ( 192 )
b = 13.8564...
b = 13.86 ( to 2 decimal places )
FINAL ANSWER:
Therefore, the length of QR is 13.86 centimetres to 2 decimal places.
Hope this helps! :)
Have a lovely day! <3
In order to find the distance covered in 1 minute, we need to divide distance covered 2 1/6 miles by 20 minutes.We are given : Ariel swims 2 1/6 miles in every 1/3 hour.
Let us convert 1/3 hour into minutes.
There are 60 minutes in an hour.
Therefore, 1/3 hours = 60 × 1/3 = 20 minutes.
So, we could say, "Ariel swims 2 1/6 miles in every 20 minutes".
2 1/6÷ 20 = 13/6 ÷ 20.
Let us convert division sign into multiplication and flip 20 to 1/20.
We get
<h3>13/6 × 1/20 = 13/120 miles in 1 minute.</h3><h3>In decimal 0.11 mile in 1 minute.</h3>
Its the difference between the y- values divided by the distance between the corresponding x values. Or its sometimes called rise / run.
Answer:
8
Step-by-step explanation:
plug in the number 4, it would be 5•4-12
Do 5•4=20
20-12=8
The solutions are (2.1925, 5.1925) and (-3.1925, -0.1925)
<em><u>Solution:</u></em>
Given that,
<em><u>We have to substitute eqn 1 in eqn 2</u></em>
Substitute x = 2.1925 in eqn 1
y = 2.1925 + 3
y = 5.1925
Substitute x = -3.1925 in eqn 1
y = -3.1925 + 3
y = -0.1925
Thus the solutions are (2.1925, 5.1925) and (-3.1925, -0.1925)
