Answer:
Step-by-step explanation:
Firstly, note that -2i really is just z = 0 + (-2)i, so we see that Re(z) = 0 and Im(z) = -2.
When we're going from Cartesian to polar coordinates, we need to be aware of a few things! With Cartesian coordinates, we are dealing explicitly with x = blah and y = blah. With polar coordinates, we are looking at the same plane but with angle and magnitude in consideration.
Graphing z = -2i on the Argand diagram will look like a segment of the y axis. So we ask ourselves "What angle does this make with the positive x axis? One answer you could ask yourself is -90°! But at the same time, it's 270°! Why do you think this is the case?
What about the magnitude? How far is "-2i" stretched from the typical "i". And the answer is -2! Well... really it gets stretched by a factor of 2 but in the negative direction!
Putting all of this together gives us:
z = |mag|*(cos(angle) + isin(angle))
= 2*cos(270°) + isin(270°)).
To verify, let's consider what cos(270°) and sin(270°) are.
If you graph cos(x) and look at 270°, you get 0.
If you graph sin(x) and look at 270°, you get -1.
So 2*(cos(270°) + isin(270°)) = 2(0 + -1*i) = -2i as expected.
Not necessarily. the absolute value of a number is that number's distance from 0 on a number line. if your taking the absolute value of a negative value, what you stated would be true. however, what if you took the absolute value of a positive number? hope that answers your question.
!5% is equivalent to 15 parts over the whole 100 part. It is written in proportions as 15/100.
Similarly, you need to find how many parts in 80 are equivalent to 15%or 15/100. So, just equate both equation with x as an unknown.
x/80 = 15/100
x = (15/100)*80
x = 12
Thus, the 15% of 80 is 12.
Answer:
H = V0y t - 1/2 g t^2 equation for vertical height of object with initial speed (V0y = V0 sin theta)
If H is to be considered an absolute value from t = 0
h = H + 3 = V0y t - 1/2 g t^2 + 3 where h is height from ground
Answer:
A
Step-by-step explanation:
The slope of a vertical line is undefined
The slope of a horizontal line is 0
