2 years ago

Hey! Can someone please answer this?

2 answers:

7 0

This picture should provide a full answer. What I did was rearrange the equation to get Tan(x) on one side, then in order to get rid of the Tan, I used Arctan, which got us the final answer.

lys-0071 [83]2 years ago

4 0

Answer:

see explanation

Step-by-step explanation:

3tanx - 2 = 4cos35.3° ( add 2 to both sides )

3tanx = 4cos35.3° + 2 ( divide both sides by 3 )

tanx = $\frac{4cos35.3+2}{3}$ ≈ 1.75485

(b)

x = $tan^{-1}$ (1.75485) ≈ 60.3° ( to 1 dec. place )

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<img src="https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B4%7D-%5Cfrac%7B2%7D%7B3%7D" id="TexFormula1" title="\frac{3}{4}-\frac{2}{3}"

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