Question

Hey! Can someone please answer this?

Answer 1

This picture should provide a full answer. What I did was rearrange the equation to get Tan(x) on one side, then in order to get rid of the Tan, I used Arctan, which got us the final answer.

Answer 2

Answer:

see explanation

Step-by-step explanation:

3tanx - 2 = 4cos35.3° ( add 2 to both sides )

3tanx = 4cos35.3° + 2 ( divide both sides by 3 )

tanx = $\frac{4cos35.3+2}{3}$ ≈ 1.75485

(b)

x = $tan^{-1}$ (1.75485) ≈ 60.3° ( to 1 dec. place )