In AOPQ , the measure of angle Q=90^ , OQ = 33, PO = 65 , and QP = 56 What ratio represents the tangent of angle P ?
1 answer:
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Answer:
x=-3 x=-1 x=2 x=-2
Step-by-step explanation:
p(x) = (x^2 + 4x + 3)(x^2 – 4)
Set this equal to zero to find the x intercepts
0 = (x^2 + 4x + 3)(x^2 – 4)
Using the zero product property
(x^2 + 4x + 3) =0 (x^2 – 4) =0
Factor
(x+3)(x+1) =0 (x-2) (x+2)=0
Using the zero product property
x+3 =0 x+1 =0 x-2 =0 x+2 =0
x=-3 x=-1 x=2 x=-2
