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timofeeve [1]
3 years ago
15

Find the equation of the circle with center at (-1, 3) and radius of 4.

Mathematics
1 answer:
zavuch27 [327]3 years ago
7 0
I think it would be A
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Which is a factor of 6x^3+6
e-lub [12.9K]
The actual factor is 6(x + 1)(x^2 - x +1).
4 0
3 years ago
Can i get its answer?​
Komok [63]

Yo sup??

perimeter=2(l+b)

100=2(35+b)

b=15 cm

area=b*h

=35*15

=525 cm²

Hope this helps

4 0
3 years ago
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If the total labor cost is $865,000 and 12 percent is for concession staff, how much of the labor cost is for concession staff?
stepladder [879]
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4 0
3 years ago
find the value of x2 values that separate the middle 90% from the rest of the distribution for 8 degrees of freedom
Anettt [7]

Answer:

With alpha 0.95 and 8 degrees of freedom χ²= 2.73

And with alpha 0.05 and 8 degrees of freedom χ²=15.51

Step-by-step explanation:

The significance level ∝ = 1- 0.9 = 0.1

But we need the area of the middle so we divide this significance level with 2

so that we get exactly the middle area .

Dividing 0.1/2= 0.05

So we will have two values for chi square

One with  0.9 + 0.05 = 0.95 alpha and one with 0.05 alpha . This is because the chi square is right tailed.

So with alpha 0.95 and 8 degrees of freedom χ²= 2.73

And with alpha 0.05 and 8 degrees of freedom χ²=15.51

This can be shown with a graph.

4 0
3 years ago
Question 12<br> With steps please
34kurt

Answer:\ \boxed{5^2}

\sqrt[n]{a}=a^\frac{1}{n}\\\\\text{therefore}\\\\\sqrt5=5^\frac{1}{2}\\----------------\\25=5^2\\----------------\\78,125=5^7\\----------------\\\text{use}\\\\a^n\cdot a^m=a^{n+m}\\\\\dfrac{a^n}{a^m}=a^{n-m}\\----------------\\\\\dfrac{\sqrt5\times78,125}{25\times5^{\frac{7}{2}}}=\dfrac{5^\frac{1}{2}\times5^7}{5^2\times5^\frac{7}{2}}=\dfrac{5^{\frac{1}{2}+7}}{5^{2+3\frac{1}{2}}}=\dfrac{5^{7\frac{1}{2}}}{5^{5\frac{1}{2}}}=5^{7\frac{1}{2}-5\frac{1}{2}}=\boxed{5^2}

6 0
3 years ago
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