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Lesechka [4]
2 years ago
13

Y=-2x2+12x-26

Mathematics
1 answer:
Elis [28]2 years ago
4 0

Answer:

y = 12x - 22

Step-by-step explanation:

If we first write the equation in vertex form and we identify it (I think you meant to simplify y) we get y = 12x - 22 as your answer!

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Serga [27]
It’s 0.09 or .09. Hope this helps:)
3 0
3 years ago
Round 38562.7 to 1 significant figure
MissTica
= 488000
(real number)

= 4.88 × 105
(scientific notation)

<span>= 4.88e5 


maybe this will help ?</span>
6 0
3 years ago
Read 2 more answers
What are the domain restrictions of the expression g2−7g+10g3−6g2+8g ? Select each correct answer.
Sauron [17]

Answer with Step-by-step explanation:

We are given that an expression

f(g)=\frac{g^2-7g+10}{g^3-6g^2+8g}

We have to find domain restriction of the given function.

f(g)=\frac{(g-5)(g-2)}{g(g-4)(g-2)}

Domain restriction means : It is that value of x when substitute in function then  function will  not defined.

It means it is that values which makes denominator zero.

From given function we can see that

When substitute g=0 then it makes denominator zero.

Hence, the function is not defined at g=0

Substitute g=4

Then, it makes denominator zero.

Hence, function is not defined  at g=4

Substitute g=2

Then,it  makes denominator zero.

Hence, function is not defined  at g=2

Therefore, the function is defined for all values of g except g=0, g=2 and g=4

5 0
3 years ago
Please help me understand this.Will mark brainlyist to right answer no links!!!
SSSSS [86.1K]
Wowowow
Answer:45
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4 0
3 years ago
Solve the system of equations given below.<br> -5x = y – 5<br> -2y = -x-21
irakobra [83]

Answer:

<h2>x = -1, y = 10 → (-1, 10)</h2>

Step-by-step explanation:

\left\{\begin{array}{ccc}-5x=y-5&\text{subtract y from both sides}\\-2y=-x-21&\text{add x to both sides}\end{array}\right\\\left\{\begin{array}{ccc}-5x-y=-5&\text{multiply both sides by (-2)}\\x-2y=-21\end{array}\right\\\underline{+\left\{\begin{array}{ccc}10x+2y=10\\x-2y=-21\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad11x=-11\qquad\text{divide both sides by 11}\\.\qquad x=-1\\\\\text{put the value of x to the first equation:}\\\\10(-1)+2y=10\\-10+2y=10\qquad\text{add 10 to both sides}\\2y=20\qquad\text{divide both sides by 2}\\y=10

3 0
3 years ago
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