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Reil [10]
3 years ago
10

Z Points

Mathematics
1 answer:
vazorg [7]3 years ago
6 0

<u>Answer:</u>

The equation of the line (-1/2, 3) and (0, 0) is y = -6x

<u>Solution:</u>

Given, two points are (\frac{-1}{2} , 3) and (0, 0)

We have to find the line equation that passes through the given two points.

Now, we know that, line equation that passes through \left(x_{1}, y_{1}\right) \text { and }\left(x_{2}, y_{2}\right) is given by:

y-y_{1}=\left(\frac{y_{2}-y_{1}}{x_{2}-x_{1}}\right)\left(x-x_{1}\right)

Here in our problem, x_{1}=0, y_{1}=0, x_{2}= \frac{-1}{2} \text { and } y_{2}=3

Substitute these values in above formula.

y-0=\left(\frac{3-0}{\frac{-1}{2}-0}\right)(x-0) \rightarrow y=\frac{3}{\frac{-1}{2}} \times x \\\\\rightarrow y=3 \times\left(\frac{-2}{1}\right) \times x \rightarrow y=-6 x

Hence the equation of the line (-1/2, 3) and (0, 0) is y = -6x

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