Hi there!
We are given:
cos(7x)cos(4x) = -1 - sin(7x)sin(4x)
Begin by moving all terms with variables to one side:
cos(7x)cos(4x) + sin(7x)sin(4x) = -1
The corresponding trig identity is cos(A - B). Thus:
cos(7x - 4x) = cos(7x)cos(4x) + sin(7x)sin(4x) = -1
cos(3x) = -1
cos = -1 at π, so:
3x = π
x = π/3
We can also find another solution. Let 3π = -1:
3x = 3π
x = π
Thus, solutions on [0, 2π) are π/3 and π.
Answer:
<em>The equation of the circle (x +1) )² +(y-(2))² = (2(√5))²</em>
<em> or </em>
<em>The equation of the circle x² + 2 x + y² - 4 y = 15</em>
<u>Step-by-step explanation:</u>
Given points end Points are p(-3,-2) and q( 1,6)
<em>The distance of two points formula</em>
P Q =
P Q =
P Q =
<em>The diameter 'd' = 2 r</em>
2 r = √80
=
=
<em> r = 2√5</em>
<em>Mid-point of two end points </em>
<em> </em><em></em>
<em> = (-1 ,2)</em>
<em>Mid-point of two end points = center of the circle</em>
<em> (h,k) = (-1 , 2)</em>
The equation of the circle
(x -h )² +(y-k)² = r²
<em> (x -(-1) )² +(y-(2))² = (2(√5))²</em>
<em> x² + 2 x + 1 + y² - 4 y + 4 = 20</em>
<em> x² + 2 x + y² - 4 y = 20 -5</em>
<em> x² + 2 x + y² - 4 y = 15</em>
<u><em>Final answer</em></u><em>:-</em>
<em>The equation of the circle (x +1) )² +(y-(2))² = (2(√5))²</em>
<em> or </em>
<em>The equation of the circle x² + 2 x + y² - 4 y = 15</em>
<em> </em>