N'(-2,2)
G'(-2,-4)
H'(6,-4)
Answer:
h(8q²-2q) = 56q² -10q
k(2q²+3q) = 16q² +31q
Step-by-step explanation:
1. Replace x in the function definition with the function's argument, then simplify.
h(x) = 7x +4q
h(8q² -2q) = 7(8q² -2q) +4q = 56q² -14q +4q = 56q² -10q
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2. Same as the first problem.
k(x) = 8x +7q
k(2q² +3q) = 8(2q² +3q) +7q = 16q² +24q +7q = 16q² +31q
_____
Comment on the problem
In each case, the function definition says the function is not a function of q; it is only a function of x. It is h(x), not h(x, q). Thus the "q" in the function definition should be considered to be a literal not to be affected by any value x may have. It could be considered another way to write z, for example. In that case, the function would evaluate to ...
h(8q² -2q) = 56q² -14q +4z
and replacing q with some value (say, 2) would give 196+4z, a value that still has z as a separate entity.
In short, I believe the offered answers are misleading with respect to how you would treat function definitions in the real world.
Answer:
x = 20
Step-by-step explanation:
hmu for more information
Answer and explanation:
Given : The position of an object moving along an x axis is given by 
where x is in meters and t in seconds.
To find : The position of the object at the following values of t :
a) At t= 1 s
b) At t= 2 s
c) At t= 3 s
d) At t= 4 s
(e) What is the object's displacement between t = 0 and t = 4 s?
At t=0, x(0)=0
At t=4, x(4)=14.24
The displacement is given by,
(f) What is its average velocity from t = 2 s to t = 4 s?
At t=2, x(2)=-1.76
At t=4, x(4)=14.24
The average velocity is given by,
Answer:
Step-by-step explanation:
I=PRT/100
I=5000*10*4=200,000/100
I=$2000
