I'll try it.
I just went through this twice on scratch paper. The first time was to
see if I could do it, and the second time was because the first result
I got was ridiculous. But I think I got it.
You said <span><u>3sin²(x) = cos²(x)</u>
Use this trig identity: sin²(x) = 1 - cos²(x)
Plug it into the original equation for (x).
3(1 - cos²(x) ) = cos²(x)
Remove parentheses on the left: 3 - 3cos²(x) = cos²(x)
Add 3cos²(x) to each side: 3 = 4cos²(x)
Divide each side by 4 : 3/4 = cos²(x)
Take the square root of each side: <em>cos(x) = (√3) / 2</em> .
There it is ... the cosine of the unknown angle.
Now you just go look it up in a book with a table cosines,
or else pinch it through your computer or your calculator,
or else just remember that you've learned that
cos( <em><u>30°</u></em> ) = </span><span><span>(√3) / 2 </span>.
</span>
Answer:
6
Step-by-step explanation:
20 jumps because 45/20 is 2.5 and 8 x 2.5 is 20.
Area of the square:
A = s²
and s = AB = sqrt ( ( 4 - 1 )² + ( 3 - 1 )² )
s = √ ( 9 + 4 ) = √ 13
A = ( √13 )² = 13
Answer: Area of the square is 13 units².
The answer of all of this is 18 because 18.1 months so if you do the math you get 18-7x+20^2
