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3 years ago

Areas that reflect light well are called

Physics

1 answer:

marishachu [46]3 years ago

6 0

Answer:

specular reflection

Explanation:

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At its peak, a tornado is 74.0 m in diameter and carries 335-km/h winds. What is its angular velocity in revolutions per second?

artcher [175]

Answer:

0.399 rev/s

Explanation:

Given that,

The diameter of a tornado, d = 74 m

Radius, r = 37 m

Linear velocity, v = 335 km/h = 93.05 m/s

We need to find the angular velocity in revolutions per second. Let it is $\omega$ . The relation between angular velocity and linear velocity is as follows :

$v=r\omega\\\\\omega=\dfrac{v}{r}\\\\\omega=\dfrac{93.0556}{37}\\\\\omega=2.51\ rad/s$

$\omega=\dfrac{2.51}{2\pi}\\\\\omega=0.399\ rev/s$

So, the angular velocity of the blade is 0.399 rev/s.

4 0

3 years ago

When an apple falls towards the earth, the earth moves up to meet the apple . Is this true ? If yes . Why is the earth's motion

choli [55]

No , I think it’s false

7 0

3 years ago

A 1.50-m cylinder of radius 1.10 cm is made of a complicated mixture of materials. Its resistivity depends on the distance x fro

MArishka [77]

Answer:

Resistance = 3.35* $10^{-4}$ Ω

Explanation:

Since resistance R = ρ $\frac{L}{A}$

whereas $\rho(x) = a + bx^2$

resistivity is given for two ends. At the left end resistivity is $2.25* 10^{-8}$ whereas x at the left end will be 0 as distance is zero. Thus

$2.25*10^{-8} = a + b(0)^2\\ 2.25*10^{-8} = a + 0 \\2.25*10^{-8} = a$

At the right end x will be equal to the length of the rod, so $x = 1.50\\8.50*10^{-8} = (2.25*10^{-8}) + ( b* (1.50)^2 )\\8.50*10^{-8} - (2.25*10^{-8}) = b*2.25\\\frac{6.25*10^{-8}}{2.25} = b\\b = 2.77 *10^{-8}$

Thus resistance will be R = ρ $\frac{L}{A}$

where A = π $r^2$

so,

$R = \frac{8.50*10^{-8} * 1.50}{3.14*(1.10*10^{-2})^2} \\R=3.35 * 10 ^{-4}$

6 0

3 years ago

The two types of waves are ……………………………………wave and …………………………

Annette [7]

Answer:

longitudinal and transverse.

Explanation:

plzzzzzzz Mark my answer in brainlist

4 0

3 years ago

A student is about to sled down a hill. He stands on a hill which is 30 meters tall and he weighs 40kg what is his GPE

PolarNik [594]

Answer:

11760J

Explanation:

Given parameters:

Height of hill = 30m

Weight = 40kg

Unknown:

Gravitational potential energy = ?

Solution:

To find the gravitational potential energy, it is the energy due to the position of a body;

G.PE = mgh

m is the mass

g is the acceleration due to gravity

h is the height

Now insert the parameters and solve;

G.PE = 40 x 9.8 x 30 = 11760J

3 0

3 years ago