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Oksana_A [137]
3 years ago
5

At its peak, a tornado is 74.0 m in diameter and carries 335-km/h winds. What is its angular velocity in revolutions per second?

Physics
1 answer:
artcher [175]3 years ago
4 0

Answer:

0.399 rev/s

Explanation:

Given that,

The diameter of a tornado, d = 74 m

Radius, r = 37 m

Linear velocity, v = 335 km/h = 93.05 m/s

We need to find the angular velocity in revolutions per second. Let it is \omega. The relation between angular velocity and linear velocity is as follows :

v=r\omega\\\\\omega=\dfrac{v}{r}\\\\\omega=\dfrac{93.0556}{37}\\\\\omega=2.51\ rad/s

or

\omega=\dfrac{2.51}{2\pi}\\\\\omega=0.399\ rev/s

So, the angular velocity of the blade is 0.399 rev/s.

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