Question

At its peak, a tornado is 74.0 m in diameter and carries 335-km/h winds. What is its angular velocity in revolutions per second?

Answer 1

Answer:

0.399 rev/s

Explanation:

Given that,

The diameter of a tornado, d = 74 m

Radius, r = 37 m

Linear velocity, v = 335 km/h = 93.05 m/s

We need to find the angular velocity in revolutions per second. Let it is $\omega$. The relation between angular velocity and linear velocity is as follows :

$v=r\omega\\\\\omega=\dfrac{v}{r}\\\\\omega=\dfrac{93.0556}{37}\\\\\omega=2.51\ rad/s$

or

$\omega=\dfrac{2.51}{2\pi}\\\\\omega=0.399\ rev/s$

So, the angular velocity of the blade is 0.399 rev/s.