Question

HELP ME !!

Answer 1

Hi there! Let me know if you have any questions about my answer:

5.6 cm³

Step-by-step explanation:

For this problem, we can assume* that the ham did not have any salt before curing.

The questions tells us:

- The mass of the salt: 12 g

- The density of salt: 2.16 g/cm³

We are looking for:

- The volume of salt

Solve using dimensional analysis, or the "unit cancellation method":

Write an equation.

$V_{salt} = 12g * \frac{1 cm^{3}}{2.16g}$        

Notice that the questions includes "cm³" in the units when discussing density. Volume can be given in cm³.

We want to multiply values with their units from the question so that, when the units cancel out, you will only have cm³ left.

In this equation set-up, "g" will cancel out because one is in the numerator (top number) and another is in the denominator (bottom number).

$= \frac{12g*1 cm^{3}}{2.16g}$          Both "g" units cancel out

$= \frac{12*1 cm^{3}}{2.16}$           Multiply 12 and 1 in the numerator

$= \frac{12 cm^{3}}{2.16}$              Divide 12 by 2.16 and keep the cm³ units

$= 5.55... cm^{3}$       Keep one extra digit** to help you round. The 5 in the middle rounds to 6.

$= 5.6 cm^{3}$            Final answer

*The ham is here to confuse you. The question doesn't give us enough information about the ham. We don't know how much ham there is, and we don't know how much salt was in the ham originally.

**12 has 2 significant figures. 2.16 has 3 significant figures. Since you're multiplying or dividing them together, you want the answer to round to 2 significant figures. Learn more about significant figures here: brainly.com/question/14463143

I hope this helps! Learn about another solution method, the density formula, here:

brainly.com/question/952755

brainly.com/question/11845282