Nathaniel is going to see a movie and is taking his 2 kids. Each movie ticket costs $12

Mathematics

1 answer:

matrenka [14]2 years ago

8 0

part 1:

3.5(3)+12

10.5+12

22.5

part two:

3.5x+12

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PLS HELP ME ASAP WITH THIS WHOLE PAGE! THANK YOU SOO MUCH!!

Doss [256]

1a) The function has arrows on both ends and no place in the middle where it is not defined. Its domain is ...
All Reals

1b) The function gives no output values below -3, but it gives output values of -3 and all above that. Its range is ...
y ≥ -3

1c) For values of x less than -1, the function's output is 1. This matches g(x) and s(x). At x=0, the function's output is -3, which only matches g(x). The appropriate choice is ...
g(x)

2b) The function is only defined for 0 ≤ x < 8. This is its domain.

3) A definition might be ...
$y=\left\{ \begin{array}{rcl}x+1 & \mbox{for} & -4\le x \le 1\\-x & \mbox{for} & 1 < x \le 3 \end{array}$

6 0

3 years ago

PLEASE HELP

lbvjy [14]

any other details you could give me ?

8 0

4 years ago

Solve for x in the equation x²-12x+59=0

lyudmila [28]

${x}^{2} - 12x + 59 = 0 \\ {x}^{2} - 12x + 36 + 23 = 0 \\ {x}^{2} - 12x + 36 = - 23 \\ {(x - 6)}^{2} = - 23 \\ x - 6 = + - \sqrt{ - 23} = + - i \sqrt{23} \\ x = 6 + - i \sqrt{23}$

mean

$x = 6 + i \sqrt{23}$

$x = 6 - i \sqrt{23}$

7 0

3 years ago

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What is the area of this parallelogram? 104 m² 88 m² 56 m² 32 m²

iragen [17]

Answer: To find area of a rectangle, multiply its base (length) by its height (width). Plug in the base, 7 meters, and the height, 8 meters. So the area of Rectangle DFBE is 56 square meters.

88m

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6 0

3 years ago

You coach a basketball ball team of 12 players; 5 players must be on the floor at all times; Figuring that every player can play

makvit [3.9K]

The function "choose k from n", nCk, is defined as
nCk = n!/(k!*(n-k)!) . . . . . where "!" indicates the factorial

a) No position sensitivity.
The number of possibilities is the number of ways you can choose 5 players from a roster of 12.
12C5 = 12*11*10*9*8/(5*4*3*2*1) = 792
You can put 792 different teams on the floor.

b) 1 of 2 centers, 2 of 5 guards, 2 of 5 forwards.
The number of possibilities is the product of the number of ways, for each position, you can choose the required number of players from those capable of playing the position.
(2C1)*(5C2)*(5C2) = 2*10*10 = 200
You can put 200 different teams on the floor.

4 0

3 years ago