Answer : The mass of oxygen per gram of sulfur for sulfur dioxide and sulfur trioxide is, 0.997 g and 1.5 g respectively.
Explanation : Given,
Mass of oxygen in sulfur dioxide = 3.49 g
Mass of sulfur in sulfur dioxide = 3.50 g
Mass of oxygen in sulfur trioxide = 9.00 g
Mass of sulfur in sulfur trioxide = 6.00 g
Now we have to calculate the mass of oxygen per gram of sulfur for sulfur dioxide and sulfur trioxide.
Mass of oxygen per gram of sulfur for sulfur dioxide = 
Mass of oxygen per gram of sulfur for sulfur dioxide = 
and,
Mass of oxygen per gram of sulfur for sulfur trioxide =
Mass of oxygen per gram of sulfur for sulfur trioxide = 
Thus, the mass of oxygen per gram of sulfur for sulfur dioxide and sulfur trioxide is, 0.997 g and 1.5 g respectively.
Answer:
answer answer answer answer answer
Multiply amount in grams by the relative atomic mass of magnesium then multiply by avagodro constant (6.02*10^23)
Answer:
Point Z
Explanation:
The river flows this direction pushing the water pollution to Point Z
Answer:
<u>The half-reaction that occurs on the anode of an electrolytic cell is called oxidation.
</u>
This can easily be depicted by a chemical reaction as such <u>"Zn(s) = Zn2+ (aq) + (2e-)"
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While, the Zinc in this reaction loses two elections. Hence copper gains those electrons and becomes solid.
<em>These reactions occurring on the anode are called positive reactions.
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While the reaction that occurs on the cathode is called reduction. This reaction can be represented by this equation "<u>Cu2+ (aq) + 2e- = Cu(s)</u>".
<u>These non-spontaneous reactions occurring in an electrolytic cell together are called redox reactions. These generate electrical energy.</u>
