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sesenic [268]
3 years ago
14

A solution of ammonia has a pH of 11.8. What is the concentration of OH– ions in the solution?

Chemistry
2 answers:
Lapatulllka [165]3 years ago
8 0

Answer:

The hydroxide concentration in the solution is 0.0063 M.

Explanation:

The pH of the solution is defined as negative logarithm of H^+ concentration.

pH=-\log[H^+]

The pH of the ammonia solution is 11.8

pH + pOH = 14

pOH = 14 - 11.8 = 2.2

The pOH of the solution is defined as negative logarithm of hydroxide ion concentration.

pOH=-\log[OH^-]

2.2=-\log[OH^-]

[OH^-]=0.0063 M

The hydroxide concentration in the solution is 0.0063 M.

melomori [17]3 years ago
7 0
[OH-]: <span>0.0063095734448</span>
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The combustion of 1.38 grams of a compound which contains C, H, O and N yields 1.72 grams of CO2 and 1.18 grams of H2O. Another
I am Lyosha [343]

Answer:

The empirical formula is C3H10N2O2

Explanation:

Step 1: Data given

Mass of the sample in experiment 1 = 1.38 grams

Mass of CO2 produced = 1.72 grams

Mass of H2O produced = 1.18 grams

Molar mass CO2 = 44.01 g/mol

Molar mass H2O = 18.02 g/mol

Atomic mass C = 12.01 g/mol

Atomic mass O = 16.0 g/mol

Atomic mass H = 1.01 g/mol

MAss of the sample in experiment 2 = 22.34 grams

Mass of O = 6.75 grams

Step 2: Calculate moles CO2

Moles CO2 = mass CO2 / molar mass CO2

Moles CO2 = 1.72 grams / 44.01 g/mol

Moles CO2 = 0.0391 moles

Step 3: Calculate moles C

For 1 mol CO2 we have 1 mol C

For 0.0391 moles CO2 we have 0.0391 moles C

Step 4: Calculate mass C

Mass C = 0.0391 moles * 12.01 g/mol

Mass C = 0.470 grams

Step 5: Calculate moles H2O

Moles H2O = 1.18 grams / 18.02 g/mol

Moles H2O = 0.0655 moles

Step 6: Calculate moles H

For 1 mol H2O we have 2 moles H

For 0.0655 moles H we have 2*0.0655 = 0.131 moles H

Step 7: Calculate mass H

Mass H = 0.131 moles * 1.01 g/mol

Mass H = 0.132 grams

Step 8: Calculate the mass %

% C = (0.470 grams / 1.38 grams) * 100 %

% C = 34.06 %

%H = (0.132/1.38)*100 %

%H = 9.57 %

%O= (6.75 grams / 22.34 grams)*100 %

%O = 30.21 %

%N = 100 % - 34.06 % - 9.57 % - 30.21 %

%N = 26.16 %

Step 8: Calculate moles in compound

Let's assume 100 grams sample then we have:

Mass C = 34.06 grams

Mass H = 9.57 grams

Mass O = 30.21 grams

Mass N = 26.16 grams

Moles C= 34.06 grams / 12.01 g/mol

Moles C= 2.836 moles

Moles H = 9.57 grams / 1.01 g/mol

Moles H = 9.475 moles

Moles O = 30.21 grams / 16.0 g/mol

Moles O = 1.888 moles

Moles N = 26.16 grams / 14.0 g/mol

Moles N = 1.869 moles

Step 9: Calculate mol ratio

We have to divide by the smallest amount of moles

C: 2.836 moles / 1.869 moles = 1.5

H: 9.475 moles /1.869 moles = 5

O: 1.888 moles /1.869 moles = 1

N: 1.869 moles / 1.869 moles = 1

This means for each mol O we have 1.5 moles C, 5 moles H and 1 mol N

OR

For every 2 O atoms we have 3 C atoms, 10 H atoms and 2 N atoms

The empirical formula is C3H10N2O2

6 0
3 years ago
7. Lli(s) + N₂(g) → 2 Liz Ncs)
timurjin [86]

The number of mole of lithium, Li needed for the reaction is 3.2 moles (Option D)

<h3>Balanced equation </h3>

4Li + N₂(g) → 2Li₂N

From the balanced equation above,

2 moles of Li₂N were obtained from 4 moles of Li

<h3>How to determine the mole of lithium needed </h3>

From the balanced equation above,

2 moles of Li₂N were obtained from 4 moles of Li

Therefore,

1.6 moles of Li₂N will be obtained from = (1.6 × 4) / 2 = 3.2 moles of Li

Thus, 3.2 moles of Li are needed for the reaction

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What is the total number of electrons in As-3?
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Answer:

Arsenic, As, has atomic number 33, which is the number of protons in the nuclei of its atoms. A neutral As atom would also have 33 electrons. The electron configuration of a neutral arsenic atom is [Ar]3d104s24p3

Explanation:

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Since Qp>Kp , the reaction is not at equilibrium.

<h3>What is the equilibrium constant?</h3>

The equilibrium constant shows the extent to which reactants are converted into products.

Now we have to obtain the Qp as follows;

Qp =[CH3OH]/[CO] [H2]^2

Qp = 0.265/(0.265) (0.265)^2

Qp = 14.2

Now we know that Kp = 6.09×10−3, Since Qp>Kp , the reaction is not at equilibrium.

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2 years ago
The circles in the model represent atmospheric layers. Make each description with the correct name of each layer.
Masja [62]

Answer:

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