<span>disproportionation is a type of redox reaction in which an element can undergo both oxidation and reduction.
Let's take a look at the choices:
First we have the oxide ion. Oxide ion has a charge of -2 which is the lowest charge that an oxygen atom can have. Therefore, an oxide ion cannot be further reduced, so this choice is not correct.
Next we have the peroxide ion. The oxygen has a charge of -1 which means it can be further reduced. So, this choice is acceptable
Last but not least, we have the superoxide ion. The oxygen has a charge of -1/2 which means it can be further reduced. So, this choice is also acceptable.
Based on this, we have two accepted choices which are b and c.</span>
1) Excess reagent
1 mol N2 / 3 mol H2
6.0 mol N2 *3 mol H2 / 1 mol N2 = 18 mol H2
18mol H2 > 12 mol H2 => H2 is limiting (you need 18 mol H2 to use all the 6 mol N2), then N2 is in excees.
12.0 mol H2 * 1mol N2/ 3 mol H2 = 4 mol N2 is the quantity that will react, then the excess is 6 mol N2 - 4 mol N2 = 2 mol N2
2) NH3 produced
12 mol H2 * [2 mol NH3 / 3 mol H2] = 8 mol NH3
Aslso, 4 mol N2 *[2molNH3 / 1 molN2] = 8 mol NH3, the same result.
3) Yield
80% * 8 mol NH3 = 6.4 mol NH3
The information given in the question is not enough to determine the acidity of the solution. This is because, acidity can only be found with the equation: pH = -log [H+].
In order to determine the acidity of the solution, the half titration point value is needed, this will make it possible to determine the value of H30+. If the half point titration value is known, then Ka will be equivalent to pH and the value will be evaluated using the equation: - log (1.6 * 10^-10).
Answer:
Using the periodic table of the elements to find atomic weights, we find that hydrogen has an atomic weight of 1, and oxygen's is 16. In order to calculate the molecular weight of one water molecule, we add the contributions from each atom; that is, 2(1) + 1(16) = 18 grams/mole.
Explanation:
hope this helped
Answer:
4,3,2
Explanation:
if you balance a chemical equation that is the correct coefficients to be placed in the blank space
