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blagie [28]
3 years ago
9

If an acid has a ka=1.6x10^-10, what is the acidity of the solution?

Chemistry
1 answer:
LUCKY_DIMON [66]3 years ago
5 0
The information given in the question is not enough to determine the acidity of the solution. This is because, acidity can only be found with the equation: pH = -log [H+].
 In order to determine the acidity of the solution, the half titration point value is needed, this will make it possible to determine the value of H30+.  If the half point titration value is known, then Ka will be equivalent to pH and the value will be evaluated using the equation: - log (1.6 * 10^-10).
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3 years ago
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Answer:

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Explanation:

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PV = nRT

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By putting values,

1 atm × V = 2.0 mol × 0.0821 atm.L/ mol.K  × 273.15 K

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