C(5) + O2(g)
Hope this helped
<span>The metal that would more easily lose an electron would be potassium. It is more reactive than sodium. Also, looking on the periodic table, </span><span>from top to bottom for groups 1 and 2, reactivity increases. So, it should be potassium. Hope this answers the question. Have a nice day.</span>
Answer:
393.1 KPa
Explanation:
Now we have to use the general gas equation;
P1V1/T1 = P2V2/T2
P1= initial pressure of the gas= 1.00atm
V1 = initial volume= 700.0 ml
T1= initial temperature= 0.0°C +273= 273K
V2= final volume= 200.0 ml
T2= final temperature =30.0°C +273= 303 K
P2= final pressure =????
Therefore;
P2= P1V1T2/ V2T1
P2= 1.00 × 700.0 × 303/ 200.0 × 273
P2= 3.88 atm
But
1 atm = 101.325 kilopascals
Therefore 3.88 atm = 3.88 × 101.325 kilopascals = 393.1 KPa
Answer:
The group 14 elements all have ns2np2 valence electron configurations. All form compounds in which they formally lose either the two np and the two ns valence electrons or just the two np valence electrons, giving a +4 or +2 oxidation state, respectively
Explanation:
