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Romashka-Z-Leto [24]
4 years ago
13

What is the product (8 x 10^2) x (2.5 x 10^2)

Chemistry
1 answer:
Likurg_2 [28]4 years ago
7 0
The answer is D. 2 x 10^5 = 200000, and the main answer is 200000.
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If we change the pH of a substance is this a physical change chemical change or both?
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3 years ago
An unknown concentration of sodium thiosulfate, Na2S2O3, is used to titrate a standardized solution of KIO3 with excess KI prese
Maru [420]

Answer: The molarity of Na_2S_2O_3 is 0.108 M

Explanation:

KIO_3+5KI+3H_2SO_4\rightarrow 3K_2SO_4+3H_2O+3I_2

2Na_2S_2O_3+I_2\rightarrow Na_2S_4O_6+2NaI

To calculate the number of moles for given molarity, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}    

\text{Moles of }KIO_3=\frac{0.0131mol/L\times 21.55}{1000}=2.8\times 10^{-4}mol

1 mole of KIO_3  produces = 3 moles of   I_2

2.8\times 10^{-4} moles of KIO_3 produces = \frac{3}{1}\times 2.8\times 10^{-4}=8.4\times 10^{-4} moles of I_2  

Now 1 mole of I_2 uses = 2 moles of Na_2S_2O_3

8.4\times 10^{-4} moles of I_2 uses =  \frac{2}{1}\times 8.4\times 10^{-4}=1.69\times 10^{-3}  moles of Na_2S_2O_3

\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution in L}}=\frac{1.69\times 10^{-3}\times 1000}{15.65}=0.108M

The molarity of Na_2S_2O_3 is 0.108 M  

6 0
3 years ago
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