Red blood cells. Need glucose oxygen to convert to carbon dioxide
<h2>
1.25 g of
would be produced from the complete reaction of 25 mL of 0.833 mol/L
with excess
</h2>
Explanation:
To calculate the number of moles for given molarity, we use the equation:


According to stoichiometry:
1 mole of
will give = 1 mole of 
0.0208 moles of
will give =
of 
Mass of 
Thus 1.25 g of
would be produced from the complete reaction of 25 mL of 0.833 mol/L
with excess
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Because alcohol expands over small temp changes, hence while a vial of it is used in sprinklers as the stop plug; the room gets hotter, the plug shatters.
The relative molecular mass of the gas : 64 g/mol
<h3>Further explanation</h3>
Given
Helium rate = 4x an unknown gas
Required
The relative molecular mass of the gas
Solution
Graham's Law

r₁=4 x r₂
r₁ = Helium rate
r₂ = unknown gas rate
M₁= relative molecular mass of Helium = 4 g/mol
M₂ = relative molecular mass of the gas
Input the value :
