"Endothermic" is the way among the following choices given that you would <span>classify the following chemical reaction, in terms of energy. The correct option among all the options that are given in the question is the second option or option "B". I hope that the answer has come to your help.</span>
Answer:
See explanation and image attached
Explanation:
A bond line structure refers to any structure of a covalent molecule wherein the covalent bonds present in the molecule are represented with a single line for each level of bond order.
The bond-line structure of CH3CH2O(CH2)2CH(CH3)2 has been shown in the image attached. We know that oxygen has a lone pair of electrons and this has been clearly shown also in the image attached.
Answer:
EXPERIMENT: THE CABBAGE INDICATOR
Here are your goals for this lesson:
Use indicator for each substance to determine if substance is an acid or a base
Summarize results and the experimental method
You can use the natural indicator in red cabbage juice to determine which household liquids are acids or bases. If no change in the color of the cabbage juice takes place, the liquid is neither an acid nor base; it is neutral.
Acids and bases are opposites. When an acids and base are mixed, they neutralize each other. You can use an indicator to see the neutralized reaction. The cabbage juice will change color when the liquids are neutralized.
Online Lab
This video will demonstrate how an indicator, in this case, cabbage indicator, can be used to determine whether a solution is acidic or basic. As you watch the video, remember to record your data and observations to use to present your findings.
Compile a summary of your findings from this experiment. Include your hypothesis, observations, data, and conclusions. Be sure to answer the questions below as well as explaining the method and results.
r.
Explanation:
For this item, we need to assume that air behaves like that of an ideal gas. Ideal gases follow the ideal gas law which can be written as follow,
PV = nRT
where P is the pressure,
V is the volume,
n is the number of mols,
R is the universal gas constant, and
T is temperature
In this item, we are to determine first the number of moles, n. We derive the equation,
n = PV /RT
Substitute the given values,
n = (1 atm)(5 x 10³ L) / (0.0821 L.atm/mol.K)(0 + 273.15)
n = 223.08 mols
From the given molar mass, we calculate for the mass of air.
m = (223.08 mols)(28.98 g/mol) = 6464.9 g
<em>ANSWER: 6464.9 g</em>
