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Svetradugi [14.3K]
3 years ago
15

The correct answer of (43.678)(64.1)

Chemistry
1 answer:
goblinko [34]3 years ago
5 0

Answer:

2,799.7598

Explanation:

If you like my answer than please mark me brainliest thanks

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Suppose that 0.1000 mole each of H2and I2are placed in a 1.000-L flask, stoppered, and the mixture is heated to 425oC. At equili
Katen [24]

<u>Answer:</u> The value of equilibrium constant for the given reaction is 56.61

<u>Explanation:</u>

We are given:

Initial moles of iodine gas = 0.100 moles

Initial moles of hydrogen gas = 0.100 moles

Volume of container = 1.00 L

Molarity of the solution is calculated by the equation:

\text{Molarity of solution}=\frac{\text{Number of moles}}{\text{Volume}}

\text{Molarity of iodine gas}=\frac{0.1mol}{1L}=0.1M

\text{Molarity of hydrogen gas}=\frac{0.1mol}{1L}=0.1M

Equilibrium concentration of iodine gas = 0.0210 M

The chemical equation for the reaction of iodine gas and hydrogen gas follows:

                         H_2+I_2\rightleftharpoons 2HI

<u>Initial:</u>                0.1    0.1

<u>At eqllm:</u>          0.1-x   0.1-x   2x

Evaluating the value of 'x'

\Rightarrow (0.1-x)=0.0210\\\\\Rightarrow x=0.079M

The expression of K_c for above equation follows:

K_c=\frac{[HI]^2}{[H_2][I_2]}

[HI]_{eq}=2x=(2\times 0.079)=0.158M

[H_2]_{eq}=(0.1-x)=(0.1-0.079)=0.0210M

[I_2]_{eq}=0.0210M

Putting values in above expression, we get:

K_c=\frac{(0.158)^2}{0.0210\times 0.0210}\\\\K_c=56.61

Hence, the value of equilibrium constant for the given reaction is 56.61

6 0
3 years ago
An atom was observed with +3 charge, n = 38, and e = 28. What is the mass number of the atom?
Finger [1]

Answer: 66

Explanation: To find the mass number you would have to add the number of protons and the number of neutrons.

3 0
2 years ago
How many moles of NH3 can be produced from 30.0 mol of H2 and excess N2?
VMariaS [17]
20 mol of NH, can be produce from 30 mol o H2
6 0
3 years ago
Question : The above compound is an ether. Give thestructure
Sphinxa [80]

Answer:

The above compound is an ether. Give thestructure  of the product(s) and indicate the major mechanism of the reaction  (SN1, SN2, E1 or E2). Indicate stereochemistry when necessary.

The mechanism that explains this transformation begins with the protonation of the  ether, which allows the subsequent SN2 attack of the iodide ion. This reaction forms  ethyl iodide and ethanol, which is also converted to ethyl iodide by reaction  with excess HI.

Explanation:

The SN2 reaction (also known as bimolecular nucleophilic substitution or as an attack from the front) is a type of nucleophilic substitution, where a pair of free electrons from a nucleophile attacks an electrophilic center and binds to it, expelling another group called the leaving group. Consequently, the incoming group replaces the outgoing group in one stage. Since the two reactant species are involved in this slow limiting stage of the chemical reaction, this leads to the name bimolecular nucleophilic substitution, or SN2. Among inorganic chemicals, the SN2 reaction is often known as the exchange mechanism.

7 0
3 years ago
How many moles are in 64.8 l of f2 gas
Licemer1 [7]
6.02×[10]1 ×64.8=3900.96 moles
7 0
3 years ago
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