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3 years ago

Jaxon Rollison

Mathematics

1 answer:

faust18 [17]3 years ago

3 0

Answer:

6200

Step-by-step explanation:

first find how much she would make purely based on hours worked:

8x40 = 320 dollars

next subtract this from total on her paycheck so 692-320 is 372

we know that 372 is 6% of a number so...

$\frac{6}{100}$ x = 372

$\frac{6x}{100}$ = 372

6x= 37200(100)

x=6200 $ divide by 6

so she sold $6200 worth of merchandise to earn $372 of commission

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8x10^30/2x10^12 in scientific notation?

4vir4ik [10]

Answer:

4*10^18

Step-by-step explanation:

Easier to think of it as the factors out front (8 / 2) = 4

and subtract the exponents 30 - 12 = 18

= 4*10 ^18

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4 years ago

HELP ME!!! I wanna pass please

ale4655 [162]

The answer would be c (w = 12 feet)!

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3 years ago

Read 2 more answers

A triangle has a perimeter of 48" and the dimensions of each side are given as x+3 4x-1 2x-3

Mekhanik [1.2K]

48" means 48 inches

anyway

the perimiter is the distance around or the sum of the sides

perimiter=48=x+3+4x-1+2x-3=7x-1

48=7x-1
add 1 to both sides
49=7x
divide both sides by 7
7=x

x+3=7+3=10

4x-1=4(7)-1=28-1=27

2x-3=2(7)-3=14-3=11

the sides are 10", 27" and 11"
x=7

5 0

4 years ago

A study of 12,000 able-bodied make students at Syracuse University found that their times for the mile run were approximately No

REY [17]

Answer:

a) About 802 students ran the mile in less than 6 minutes

b) It took at least 8.06 minutes for the slowest 10% of the students to run the mile

c) 67.62% of students ran the mile in between 400 and 500 seconds.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 7.11, \sigma = 0.74$

a. About how many students ran the mile in less than 6 minutes?

Proportion who ran in less than 6 minutes is the pvalue of Z when X = 6. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{6 - 7.11}{0.74}$

$Z = -1.5$

$Z = -1.5$ has a pvalue of 0.0668

Out of 12000

0.0668*12000 = 801.6

About 802 students ran the mile in less than 6 minutes.

b. Approximately how long did it take the slowest 10% of the students to run the mile?

The slowest, the higher the time.

So this is the 100-10 = 90th percentile of times.

Which are times of X when Z = 1.28 and greater

$Z = \frac{X - \mu}{\sigma}$

$1.28 = \frac{X - 7.11}{0.74}$

$X - 7.11 = 1.28*0.74$

$X = 8.06$

It took at least 8.06 minutes for the slowest 10% of the students to run the mile

c. Suppose that these mile run times are converted from minutes to seconds. Estimate the percent of students who ran the mile in between 400 and 500 seconds.

Each minute has 60 seconds. So

$\mu = 60*7.11 = 426.6, \sigma = 44.4$