All categories

3 years ago

Point Q(-2, 8) is translated using the rule (x + 1, y - 2).

1 answer:

5 0

For this case, what you must do is apply the rule (x + 1, y - 2) to point Q (-2, 8).
Applying the rule we have
Q (-2, 8) ---> (x + 1, y - 2) ---> (-2 + 1, 8 - 2) ----> (-1, 6)
Thus,
Q '(- 1, 6)
answer
the y coordinate of Q ' is 6

You might be interested in

A parallelogram is shown below:

nordsb [41]

9514 1404 393

Answer:

A. 2 square feet

B. draw a diagonal; 1 square foot

Step-by-step explanation:

A. The area of a parallelogram is given by the formula ...

A = bh

Here the base (b) is 3 feet, and the height (h) is 2/3 ft. The area is ...

A = (3 ft)(2/3 ft) = 2 ft^2 . . . . area of the parallelogram

B. Drawing a diagonal (AC or BD) will divide the figure into two congruent triangles. Each triangle has the same base and height as the original parallelogram. The area of one of the triangles is given by ...

A = 1/2bh

Using the given dimensions, ...

A = 1/2(3 ft)(2/3 ft) = 1 ft^2 . . . . area of one triangle

7 0

3 years ago

Help! <img src="https://tex.z-dn.net/?f=%5Csf%20%5Csqrt%7Bx-2%7D-x%3D-2" id="TexFormula1" title="\sf \sqrt{x-2}-x=-2" al

Gennadij [26K]

$▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪$

Let's solve for x :

$\sqrt{x - 2} - x = - 2$

$\sqrt{x - 2} = x - 2$

$1 = \dfrac{x - 2}{ \sqrt{x - 2} }$

$1 = \sqrt{x - 2}$

$x - 2 = 1$

$x = 3$

4 0

3 years ago

<img src="https://tex.z-dn.net/?f=%5Csqrt%7B%28-81%29x%5E%7B2%7D%20%7D" id="TexFormula1" title="\sqrt{(-81)x^{2} }" alt="\sqrt{(

SSSSS [86.1K]

Answer:

We conclude that:

$\sqrt{\left(-81\right)x^2}=9ix$

Step-by-step explanation:

Given the radical expression

$\sqrt{\left(-81\right)x^2}$

simplifying the expression

$\sqrt{\left(-81\right)x^2}$

Remove parentheses: (-a) = -a

$\sqrt{\left(-81\right)x^2}=\sqrt{-81x^2}$

Apply radical rule: $\sqrt{-a}=\sqrt{-1}\sqrt{a},\:\quad \mathrm{\:assuming\:}a\ge 0$

$=\sqrt{-1}\sqrt{81x^2}$

Apply imaginary number rule: $\sqrt{-1}=i$

$=i\sqrt{81x^2}$

Apply radical rule: $\sqrt[n]{ab}=\sqrt[n]{a}\sqrt[n]{b},\:\quad \mathrm{\:assuming\:}a\ge 0,\:b\ge 0$

$=\sqrt{81}i\sqrt{x^2}$

$=9i\sqrt{x^2}$

Apply radical rule: $\sqrt[n]{a^n}=a,\:\quad \mathrm{\:assuming\:}a\ge 0$

$=9ix$

Therefore, we conclude that:

$\sqrt{\left(-81\right)x^2}=9ix$

7 0

3 years ago

Solve for the unknown quantity of x 15/2= 60/x

grin007 [14]

Answer:

Directions: Write the name and composition of the following composer/s below. Space provided for your answer.

3 0

4 years ago

A rectangular prism has a volume 144 centimeters. The base is a square with a length of 4 cm. What is the height of the prism?

Vitek1552 [10]

The volume is the product of the height and the area of the base.
V = Bh
The area of the square base is (4 cm)² = 16 cm², so the height can be found from
144 cm³ = (16 cm²)h
h = (144 cm³)/(16 cm² = 9 cm

The height of the prism is 9 cm.

6 0

3 years ago