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klasskru [66]
2 years ago
9

System of equation by using substitution 3=y+3x -x+3y=29

Mathematics
1 answer:
Marianna [84]2 years ago
5 0

Answer:

x=-2

y=9

Step-by-step explanation:

3=y+3x ---- A

-x+3y=29 ----B

step 1. rearrange equation A, so you have the "y" variable on one side

3=y+3x

-3x     -3x

3-3x=y

y=3-3x ---- C

step 2. Substitute equation C into equation B in place of "y"

-x+3(3-3x)=29 ---foil

-x+9-9x=29 -- collect like terms

-10x+9=29

       -9     -9

   -10x=20

      ÷-10     ÷-10

         x=-2

Step 3. Substitute x=-2 into equation C to find y

y=3-3(-2)

y=3+6

y=9

Check you answer by subsituting x=-2 and y=9 back into equation A and B

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The 3 × 3 matrix P satisfies the matrix equation P^2 = P.
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Answer:  The answers are given below.

Step-by-step explanation:  Given that a  3 × 3 matrix P satisfies the matrix equation P² = P.

We are to

(a) find the possibilities for the determinant of P.

(b) explain the reason behind there are no other possibilities.

(c) give an example of P, for each possible determinant.

(a) According to the given information, we have

P^2=P\\\\\Rightarrow P^2-P=0\\\\\Rightarrow P(P-I)=0\\\\\Rightarrow P=0,~~~P=I.

So, P can be either a zero matrix of order 3 or an identity matrix of order 3.

If P = 0, then det(P) = 0     and     if P = I, then det(P) = 1.

Therefore the possible determinants of P are 0 and 1.

(b) There can be any other determinant other than 0 and 1, because if so, then the given equation P² = P will not be satisfied.

(c) If |P| = 0, then the matrix P can be can be of the form as follows:

P=\left[\begin{array}{ccc}0&0&0\\0&0&0\\0&0&0\end{array}\right] .

If |P| = 1, the the matrix P can be of the form as follows :

P=\left[\begin{array}{ccc}1&0&0\\0&1&0\\0&0&1\end{array}\right] .

Thus, all the parts are answered.

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3 years ago
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Answer: None

Step-by-step explanation:

y=0 and y=-5 don't have any solutions. When you ask if a pair of equations have a solution, that means there is an intersection of the equations. The 2 equations will meet somewhere, and that is the solution. To find the solution, you set the equations equal to each other.

0≠-5

It is obvious that 0 and -5 are not equal to each other. Therefore, there is no solution. Also, y=0 and y=-5 are horizontal lines that are parallel to each other. They will never meet, which means there will be no intersection. No intersection means no solutions.

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