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guajiro [1.7K]
3 years ago
15

I'll give brainliest

Mathematics
1 answer:
Ray Of Light [21]3 years ago
7 0
The answer is 60. The formula is v=bxhxh/b or in this case 6x4x15/6. After you multiply the numerator you will get 360 and then you divide by 6 to get your answer: 60.
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Solve the system of equations y= 3/2 - 1, -x+ y =-3
kaheart [24]

Answer:

(x, y) = ( 1/2, -3 )

Step-by-step explanation:

y = -3

3/2 - 1 - x + y = - 3

3/2 - 1 - x - 3 = - 3

x = 1/2

solution : (x , y ) = ( 1/2, -3)  

here we are gonna see why is that answer :

-3 = 3/2 -1 - 1/2 - 3 = -3

-3 = -3 = -3

i hope this helps

5 0
2 years ago
The y-intercept of (2,5) and (4,4)
wolverine [178]
First let's find the slope of line joining (2, 5) and (4, 4)

Assuming points  (x₁, y₁) and (x₂, y₂)

Slope = (y₂ - y₁) / (x₂ - x₁)

Slope = (4 - 5) / (4 -2) =  -1/2 = -0.5

From equation of line:     y = mx + c

y = -0.5x + c

Using the point (2 , 5) as passing through y = -0.5x + c

x = 2, y = 5

5 = -0.5*2 + c

5 = -1 + c

5 + 1 = c

6 = c

c = 6

Therefore the y-intercept which is c = 6

y-intercept = 6

Hope this explains it.
4 0
3 years ago
Read 2 more answers
Determine the explicit formula of the following sequence -3,-18,-108...
kvv77 [185]

Answer:

a_{n} = - 3(6)^{n-1}

Step-by-step explanation:

Note the common ratio r between consecutive terms, that is

r = - 18 ÷ - 3 = - 108 ÷ - 18 = 6

This indicates the sequence is geometric with n th term ( explicit formula )

a_{n} = a(r)^{n-1}

where a is the first term and r the common ratio

Here a = - 3 and r = 6, thus

a_{n} = - 3(6)^{n-1}

3 0
3 years ago
Can someone help pls?
luda_lava [24]
84 x ___ will bring 91
5 0
3 years ago
Suppose we are interested in bidding on a piece of land and we know one other bidder is interested. The seller announced that th
Sergeeva-Olga [200]

Answer:

Step-by-step explanation:

(a)

The bid should be greater than $10,000 to get accepted by the seller. Let bid x be a continuous random variable that is uniformly distributed between

$10,000 and $15,000

The interval of the accepted bidding is [ {\rm{\$ 10,000 , \$ 15,000}], where b = $15000 and a = $10000.

The interval of the provided bidding is [$10,000,$12,000]. The probability is calculated as,

\begin{array}{c}\\P\left( {X{\rm{ < 12,000}}} \right){\rm{ = }}1 - P\left( {X > 12000} \right)\\\\ = 1 - \int\limits_{12000}^{15000} {\frac{1}{{15000 - 10000}}} dx\\\\ = 1 - \int\limits_{12000}^{15000} {\frac{1}{{5000}}} dx\\\\ = 1 - \frac{1}{{5000}}\left[ x \right]_{12000}^{15000}\\\end{array}

=1- \frac{[15000-12000]}{5000}\\\\=1-0.6\\\\=0.4

(b)  The interval of the accepted bidding is [$10,000,$15,000], where b = $15,000 and a =$10,000. The interval of the given bidding is [$10,000,$14,000].

\begin{array}{c}\\P\left( {X{\rm{ < 14,000}}} \right){\rm{ = }}1 - P\left( {X > 14000} \right)\\\\ = 1 - \int\limits_{14000}^{15000} {\frac{1}{{15000 - 10000}}} dx\\\\ = 1 - \int\limits_{14000}^{15000} {\frac{1}{{5000}}} dx\\\\ = 1 - \frac{1}{{5000}}\left[ x \right]_{14000}^{15000}\\\end{array} P(X14000)

=1- \frac{[15000-14000]}{5000}\\\\=1-0.2\\\\=0.8

(c)

The amount that the customer bid to maximize the probability that the customer is getting the property is calculated as,  

The interval of the accepted bidding is [$10,000,$15,000],

where b = $15,000 and a = $10,000. The interval of the given bidding is [$10,000,$15,000].

\begin{array}{c}\\f\left( {X = {\rm{15,000}}} \right){\rm{ = }}\frac{{{\rm{15000}} - {\rm{10000}}}}{{{\rm{15000}} - {\rm{10000}}}}\\\\{\rm{ = }}\frac{{{\rm{5000}}}}{{{\rm{5000}}}}\\\\{\rm{ = 1}}\\\end{array}

(d)  The amount that the customer bid to maximize the probability that the customer is getting the property is $15,000, set by the seller. Another customer is willing to buy the property at $16,000.The bidding less than $16,000 getting considered as the minimum amount to get the property is $10,000.

The bidding amount less than $16,000 considered by the customers as the minimum amount to get the property is $10,000, and greater than $16,000 will depend on how useful the property is for the customer.

5 0
3 years ago
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